Seq Convergence: Does a_n = (-1)^(n+1)/(2n-1) Converge or Diverge?

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Homework Help Overview

The discussion revolves around the convergence or divergence of the sequence defined by \(\displaystyle a_{n} = \frac{(-1)^{n+1}}{2n-1}\). Participants are exploring the properties of this sequence and its behavior as \(n\) approaches infinity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are considering the application of the squeeze theorem and questioning whether the sequence converges conditionally. There are inquiries about the limit of the sequence and comparisons between terms.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on the sequence's limit and properties. Some have suggested checking the conditions for convergence, while others are clarifying the nature of the problem being addressed.

Contextual Notes

There is a mention of the need for a more complete homework template, indicating that some information may be missing or unclear. Participants are also distinguishing between sequences and series in their discussions.

whatlifeforme
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Homework Statement


Converge or diverge?

Homework Equations


\displaystyle a_{n} = \frac{(-1)^{n+1}}{2n-1}

The Attempt at a Solution


all i know is to perhaps take ln of numerator and denominator to get the exponent down below?
 
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whatlifeforme said:

Homework Statement


Converge or diverge?

Homework Equations


\displaystyle a_{n} = \frac{(-1)^{n+1}}{2n-1}

The Attempt at a Solution


all i know is to perhaps take ln of numerator and denominator to get the exponent down below?
Do you know the squeeze theorem ?
 
SammyS said:
Do you know the squeeze theorem ?

I do.
 
whatlifeforme said:
I do.

It appears the sequence is conditionally convergent.

1. What is ##\sum |a_n| = \space ?##

2. Is ##a_n > a_{n+1}##? For sufficiently large n.

3. lim n→∞ ... = ...
 
whatlifeforme said:

Homework Statement


Converge or diverge?

Homework Equations


\displaystyle a_{n} = \frac{(-1)^{n+1}}{2n-1}

The Attempt at a Solution


all i know is to perhaps take ln of numerator and denominator to get the exponent down below?

Are you asking about a sequence or a series? You should fill in part one of the homework template more completely.
 
Last edited:
sequence.
 
So show us what you have done so far in thinking about whether that sequence has a limit.
 

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