- #1
joris_pixie
- 25
- 0
Hey, guys !
I have to calculate:
[tex]\sum 1/(2n + 1)^2 [/tex]
n from 0 to infinite
Knowing that 1/n² = (pi)²/6
The answer is (pi)²/8
I don't know why I'm stuck here but I just don't get it...
Greetings
I have to calculate:
[tex]\sum 1/(2n + 1)^2 [/tex]
n from 0 to infinite
Knowing that 1/n² = (pi)²/6
The answer is (pi)²/8
I don't know why I'm stuck here but I just don't get it...
Greetings
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