Series R and LC circuit question

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SUMMARY

The discussion focuses on a series RLC circuit with terminals x, y, and z, where a resistor (R) is placed between x and z, and an inductor (L) and capacitor (C) are in series between z and y. The output voltage (Vzy) is determined to be discontinuous due to the nature of the square wave input applied between x and y. The current through the inductor remains continuous, while the voltage across the capacitor experiences discontinuities at the rising edge of the square wave, necessitating the use of integral-differential equations to analyze the circuit's behavior.

PREREQUISITES
  • Understanding of series RLC circuit configurations
  • Knowledge of square wave input signals
  • Familiarity with integral-differential equations
  • Concept of continuity in electrical components (inductors and capacitors)
NEXT STEPS
  • Study the behavior of square wave inputs in RLC circuits
  • Learn how to derive integral-differential equations for RLC circuits
  • Explore the concept of voltage and current continuity in inductors and capacitors
  • Investigate simulation tools for analyzing RLC circuit responses
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Electrical engineering students, circuit designers, and anyone studying transient responses in RLC circuits will benefit from this discussion.

sylak
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Homework Statement



Since I don't have a pic.. I will explain my problem. I have a circuit with 3 terminals x , y and z.
Between x - z I have a resistance , say R,
Between z - y I have an inductor L and then a capacitor C in series.
I apply a square wave input between x and y.

Homework Equations

How will the voltage at output look like? and why does it look like it? output terminals being z-y.

The Attempt at a Solution



I already know the answer except I can't understand it. Answer being, Vzy would be discontinuous. So far, I have , at the rising edge of the square wave, an impulse current would be across L, now I don't understand how the capacitor will react. can someone explain it? so how would Vzy be discontinuous?
 
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The current through an inductor is always continuous, and the voltage across a capacitor is always continuous. Does that help?
 
Since the three elements are in series, the current is the same in all three. Write the equations of voltage as a function of the current for the three elements. The sum of the voltages is the input square wave, or a series of positive and negative steps.
Solve the resulting integral-differential equation, to obtain the current in the circuit.
Having the current, you have the voltages in the inductor and capacitor.
 

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