Series with Hyperbolic and Trigonometric functions

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SUMMARY

The series \(\sum_{n=3}^{\infty}\ln \left(\frac{\cosh \frac{\pi}{n}}{\cos \frac{\pi}{n}}\right)\) converges. The transformation of the series involves using the Taylor expansion for hyperbolic and trigonometric functions, leading to the simplification \(\sum_{n=3}^{\infty}\left(\frac{\pi^2}{n^2}+O(\frac{1}{n^4})\right)\). This indicates that the series behaves similarly to the convergent p-series \(\sum_{n=3}^{\infty}\frac{1}{n^2}\), confirming convergence.

PREREQUISITES
  • Understanding of series convergence tests
  • Familiarity with Taylor series expansions
  • Knowledge of hyperbolic and trigonometric functions
  • Basic calculus concepts, particularly limits and asymptotic notation
NEXT STEPS
  • Study the comparison test for series convergence
  • Learn about Taylor series for hyperbolic functions
  • Explore the properties of logarithmic functions in series
  • Investigate the behavior of asymptotic notations like \(O\) notation
USEFUL FOR

Mathematics students, educators, and anyone studying series convergence, particularly in the context of hyperbolic and trigonometric functions.

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Homework Statement


Determine whether the series converges and diverges.

[tex]\sum_{n=3}^{\infty}\ln \left(\frac{\cosh \frac{\pi}{n}}{\cos \frac{\pi}{n}}\right)[/tex]






The Attempt at a Solution



[tex]\sum_{n=3}^{\infty}\ln \left(\frac{1+\frac{\pi^2}{2n^2}+O(\frac{1}{n^4})}{1-\frac{\pi^2}{2n^2}+O(\frac{1}{n^4})}\right)[/tex]

[tex]=\sum_{n=3}^{\infty}\ln \left(\left(1+\frac{\pi^2}{2n^2}+O(\frac{1}{n^4})\right)\left(1+\frac{\pi^2}{2n^2}+O(\frac{1}{n^4})\right)\right)=\sum_{n=3}^{\infty}\ln \left(1+\frac{\pi^2}{n^2}+O(\frac{1}{n^4})\right)[/tex]

[tex]=\sum_{n=3}^{\infty}\left(\frac{\pi^2}{n^2}+O(\frac{1}{n^4})\right)[/tex]

series converges
 
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Sorry its not immediately obvious to me how you got the your first line of working to your second.
 

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