Set 4.5x - 9(1-x) to Equal -1 with TI 83 Calculator

  • Thread starter Thread starter Kombaiyashii
  • Start date Start date
  • Tags Tags
    Set
Kombaiyashii
Messages
5
Reaction score
0
Hi.

I would like to make the answer equal -1

here's the formula:

4.5(x) - 9(1-x)

How do I set this to equal -1? (This isn't homework, I'm working out some poker math and am not very good at this type of thing.) I use a TI 83 calculator.
 
Mathematics news on Phys.org
It's the same as 4.5(x) - 9(1-x)+1 = 0

Take a hint from me:
If you want to learn math, set your calculator aside.
 
To "set" something to -1 means to write "= -1" at the end! So to "set" 4.5x- 9(1- x) to -1 is just to write 4.5x- 9(1- x)= -1. If you mean "find the value of x that makes this true", use the usual "rules" of algebra. First multiply out those parentheses:
4.5x- 9+ 9x= -1
Add the terms in x, 13.5x- 9= -1. Now add 9 to both sides, then divide both sides by 13.5.

Using a calculator to do that is like using a calculator to add "1+ 1" (and I have seen people do that!).
 
SteamKing said:
Take a hint from me:
If you want to learn math, set your calculator aside.
+1 to that!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top