Set up an integral that represents the area of the surface generated when the region is bounded by x + y2 = 1 and the y-axis, then rotated about the y-axis. All in one-variable.
SA = 2pi [tex]\int xds[/tex]
possible x2 + y2 = r2
The Attempt at a Solution
I tried to set up an integral as a circle and somehow ended up getting 2pi[tex]\int(r/2)(2pi r) dr[/tex]
When I picture it, it would be a sphere with a radius of 1. Still don't truly understand on how to make a integral to show it