Setting up systems of forces and free body diagrams

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SUMMARY

This discussion focuses on setting up free body diagrams for a static mass on an inclined plane, specifically a car on a driveway. The main contention is between two representations, labeled A and B, of the forces acting on the mass. The correct approach is to recognize that the weight vector always points downward towards the center of the Earth, while the normal force acts perpendicular to the incline. The analysis confirms that image B accurately depicts the forces, as it correctly shows the weight's component pushing the car down the incline.

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Homework Statement


Suppose I've got a static mass on a downward plane. (For instance a car on a drive way). How would you set up this free body diagram?

Homework Equations


F = f1+f2...etc

The Attempt at a Solution


image.jpeg

My preference is A, but I've seen it displayed in examples in my book as B. Is there and difference?
In the instance of this being a mass, I used A and said W could be broken down into components of W (for Wx and Wy) and that the normal force could be broken into X and Y as well for normal and frictional forces. The problem I see is that my X components will be opposite of how they are in real life. (I.e. The weight ought to be pointing toward the left because it will roll down the plane and friction ought to be pushing it up the plane). However, if you translate the system from a normal scenario to an inclined scenario (i.e. The left sketch to A) then it ought look like A.
 

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No, image B is correct. The normal force is perpendicular to the incline, but the weight always points directly downwards (towards the center of the earth). As for your comment regarding the direction of the weight being in the direction of motion: if you project the weight vector onto the incline, you notice that some component of the weight is going to push the car to the left in image B. That isn't the case in image A.
 

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