Shield Principle Clarified: Inside-Outside Electric Field Independency

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    Principle Shielding
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Discussion Overview

The discussion revolves around the interpretation of Feynman's statement regarding the independence of electric fields inside and outside a closed conducting shell, particularly in the context of a spherical conductor with a charge in its cavity. Participants explore the implications of this principle in electrostatics and its potential inconsistencies.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants question the accuracy of Feynman's statement that no static distribution of charges inside a closed conductor can produce any fields outside, suggesting it may not apply to all scenarios.
  • One participant proposes that Feynman might be referring specifically to grounded conductors or those with a net opposing charge.
  • Another participant asserts that Feynman's original wording has been corrected in later editions to clarify that the independence applies to grounded conducting shells.
  • Some participants interpret Feynman's statement to mean that moving a charge within the cavity does not affect the external field, emphasizing the independence of the internal and external fields.
  • Reference is made to Griffiths' textbook as a source that provides further clarification on the behavior of electric fields in conductors.

Areas of Agreement / Disagreement

Participants express disagreement regarding the interpretation of Feynman's statement, with some asserting it is an error while others defend its validity under certain conditions. The discussion remains unresolved as differing viewpoints persist.

Contextual Notes

There are limitations regarding the assumptions made about the conditions under which Feynman's statement applies, particularly concerning grounded versus ungrounded conductors and the nature of the charge distribution.

babblingsia
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Consider an uncharged spherical conductor .It has a cavity carved out of it and there's a charge q in the cavity.Now you get an electric field outside the sphere.All fine.But why does Feynman say that "...no static distribution of charges inside a closed conductor can produce any fields outside.Shielding works both ways!In electrostatics-but not in varying fields- the fields on the two sides of a closed conducting shell are completely independent." Could someone please help me clear the inconsistencies?
 
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babblingsia said:
Consider an uncharged spherical conductor .It has a cavity carved out of it and there's a charge q in the cavity.Now you get an electric field outside the sphere.All fine.

Yeah, that's right.

But why does Feynman say that "...no static distribution of charges inside a closed conductor can produce any fields outside.Shielding works both ways!In electrostatics-but not in varying fields- the fields on the two sides of a closed conducting shell are completely independent." Could someone please help me clear the inconsistencies?

That' doesn't seem right. Are you sure you that's exactly how it was given in his book, and you didn't make an error while posting?

If so, he must talking about grounded conductors, or conductors which has a net opposing charge.
 
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Feynman error!

Yes, Feynman really did write that just as babblingsia stated. It's an error that has been corrected in the latest printing of the "Definitive" edition. It now reads:

...the fields on the two sides of a closed grounded conducting shell are completely independent.​

PS: When I dragged out my tattered copy of the lectures to verify the OP's quote, I noticed the notation "huh?" that I had penciled in next to that statement when I first read it decades ago. :wink:
 
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"the fields on the two sides of a closed conducting shell are completely independent."
I think he means that moving a charge wilthin a cavity (thus changing the field in the cavity) does not affect the field outside the conductor.
Sometimes Feynman's colorful language can confuse.
 
i feel what he means is the the charge distribution inside the cavity has absolutely no effetc what so ever on the outside field
 
Yep. See the example in Griffiths Introduction to ED, section on conductors. Very enlightening.
 

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