A particle moves such that its acceleration is given by: a = -β(x-2). Here β is a positive constant and c is the distance from origin What is the time period of oscillation for the particle? Solution: a = 0 at x = 2 (mean position) a = -βX where X = x-2. So, ω2 = β ⇒ T = 2π/ω = 2π/√β My question is, why do we need to substitute x-2 as X? Can't we solve the problem without doing this?