SHM: Equation relating acceleration and displacement

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Discussion Overview

The discussion revolves around the relationship between acceleration and displacement in simple harmonic motion (SHM), specifically examining the equation a = -β(x-2) and the implications of substituting x-2 as a new variable X. Participants explore the necessity and implications of this substitution in solving for the time period of oscillation.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant presents the equation a = -β(x-2) and derives the time period T = 2π/√β, questioning the need for the substitution of x-2 as X.
  • Another participant suggests that the substitution helps in recognizing the problem as SHM more readily.
  • A subsequent participant asks whether x-2 should be referred to as the distance from the mean position or simply x.
  • One participant expresses a feeling of overthinking the problem, implying a lack of complexity in the discussion.
  • Another participant confirms that x-2 represents the displacement from the equilibrium position, indicating it is a useful choice for a coordinate system.

Areas of Agreement / Disagreement

There is no clear consensus on the necessity of the substitution or its implications, as participants express differing views on its usefulness and the complexity of the problem.

Contextual Notes

The discussion does not resolve whether the substitution is essential for solving the problem or merely a matter of convenience. The participants' varying perspectives highlight different approaches to understanding SHM.

Who May Find This Useful

This discussion may be of interest to students and enthusiasts of physics, particularly those studying simple harmonic motion and the mathematical representations of motion. It may also benefit those exploring different methods of problem-solving in physics.

andyrk
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A particle moves such that its acceleration is given by: a = -β(x-2). Here β is a positive constant and c is the distance from origin What is the time period of oscillation for the particle?

Solution: a = 0 at x = 2 (mean position)
a = -βX where X = x-2.
So, ω2 = β ⇒ T = 2π/ω = 2π/√β

My question is, why do we need to substitute x-2 as X? Can't we solve the problem without doing this?
 
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you can do the whole problem without the substitution. I guess that using the substitution means that you can immediately recognise that the problem is SHM.
 
So then, would we call x-2 as the distance from the mean position or x?
 
There's not much depth involved in this. I am overthinking things.
 
yeah :) x-2 is the displacement from the equilibrium position, which makes it a convenient choice to use as coordinate, instead of using x.
 

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