Supersonic Jet: Mach 3 at Altitude 20,000m - Shock Wave & Boom Times

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SUMMARY

A supersonic jet traveling at Mach 3.00 at an altitude of 20,000 meters generates a shock wave that reaches a person directly below at a calculated time. The speed of sound in air is 335 m/s, and the time for the shock wave to reach the observer is derived from the equation d=rt. The discussion also highlights the aerodynamic design of supersonic missiles and rockets, emphasizing the importance of blunt nose shapes in creating bow shock waves to manage local heating and reduce air resistance.

PREREQUISITES
  • Understanding of Mach number and its implications in aerodynamics
  • Familiarity with basic physics equations, particularly d=rt
  • Knowledge of shock wave formation and characteristics
  • Concepts of fluid dynamics related to supersonic travel
NEXT STEPS
  • Research the principles of shock wave formation in supersonic flight
  • Study the aerodynamic design of missiles and rockets, focusing on blunt versus sharp nose shapes
  • Explore the effects of altitude on sound speed and shock wave propagation
  • Learn about the implications of Mach 3 travel on local atmospheric conditions
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in the dynamics of supersonic travel and shock wave phenomena.

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Homework Statement



A supersonic jet traveling at Mach 3.00 at an altitude of 20,000 meters is directly over a person at a time t=0 as show in figure (see below). (a) At what time will the person encounter the the shock wave? (b) Where will the plane be when the "boom" is finally heard? (Assume the speed of sound in air is 335 m/s).

IMG_1395.jpg


This is a two part problem (a & b) and I need help with part "a" only as I've already solved part "b" on my own so far.

Homework Equations



IMG_1396.jpg


The Attempt at a Solution



Well, I solved part "b" by using sin = V/Vs with V = 1 Mach and Vs = 3 Mach to get the angle ( 19.5 degrees )

Then I used Tan = y/x solving for "x" with y=20,000 meters and Tan 19.5 degrees to get 5.66x10^4 meters.

Now for part "a" I don't have a clue how to get the time since wouldn't they just cancel out anyways by looking at the equation? I've obviously ruled out kinematics equations so...yeah.
 
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Well, if the shock wave is generated when the plane is directly above the person, the time it will take to reach him would just be h/the speed of the shock wave, no?
 
entorm said:
Well, if the shock wave is generated when the plane is directly above the person, the time it will take to reach him would just be h/the speed of the shock wave, no?

Ha...I totally missed that. I used d=rt and got the time.

Thanks!
 
The nose of the super sonic missile and rocket are of blunt shape to form a bow shock wave, why?
 
Any object moving in a fluid with a speed that exceeds the sound speed of the fluid creates a shock wave, and the shape of the shock wave depends on the shape of the object. I am not an expert on missiles or rockets, but I have the impression that their noses are actually sharp, and they are designed this way to minimize air resistance.
 

no u r not right,they have blunt nose to create bow shock wave. it has to do some thing with local heating
 
no u r not right,they have blunt nose to create bow shock wave. it has to do some thing with local heating
 

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