Show by using Torricelli's law

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SUMMARY

The discussion focuses on applying Torricelli's law to a cone-shaped water tank defined by the volume function V(h) = π(h - (h²/3) + (h³/27)). The goal is to demonstrate the equation -2√2π(1/√h - (2/3)√h + (1/9)h^(3/2))(dh/dt) = 1, which relates the rate of change of water depth with time. The initial analysis reveals that the volume derivative V' = (1/9)π(h - 3)²h' is insufficient alone, indicating the need for additional information regarding fluid dynamics, such as the presence of an orifice for fluid flow.

PREREQUISITES
  • Understanding of Torricelli's law in fluid dynamics
  • Familiarity with calculus, specifically derivatives and rates of change
  • Knowledge of volume formulas for geometric shapes, particularly cones
  • Basic principles of fluid mechanics, including flow rates and orifice equations
NEXT STEPS
  • Study the derivation of Torricelli's law and its applications in fluid dynamics
  • Explore the calculus of related rates in the context of changing volumes
  • Investigate the effects of orifice size and shape on fluid flow rates
  • Learn about the mathematical modeling of fluid systems using differential equations
USEFUL FOR

This discussion is beneficial for students and professionals in engineering, particularly those specializing in fluid mechanics, as well as mathematicians interested in applied calculus and differential equations.

xaxa
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A cone-shaped water tank is given by V(h)=\pi(h-\frac{h^2}{3}+\frac{h^3}{27})

Show using Torricelli's law law that <br /> -2\sqrt2\pi(\frac{1}{\sqrt{h}}-\frac{2}{3}\sqrt h+\frac{1}{9}h^{3/2})\frac{dh}{dt}=1

What I have done so far: <br /> V&#039;=\frac{1}{9}\pi(h-3)^2h&#039;
 
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There must be more to the question statement. The given formula for V only tells you something about the shape of the vessel. The thing to be proved has the depth varying with time. Is there fluid flowing in? Out? Through what orifice?
 

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