Show Linear Independence of Set with T:V->V Operator

Click For Summary
SUMMARY

The discussion focuses on demonstrating the linear independence of the set {v, T(v), ..., T^(m-1)(v)} where T: V -> V is a linear operator on a vector space V over a field F. It is established that if v is a non-zero vector and T^m(v) equals zero while all previous applications of T yield non-zero results, then the set is linearly independent. The approach involves applying the operator T to the linear combination of the vectors and analyzing the implications of the resulting equations.

PREREQUISITES
  • Understanding of linear operators in vector spaces
  • Familiarity with the concept of linear independence
  • Knowledge of the properties of vector spaces over fields
  • Experience with applying operators repeatedly in linear algebra
NEXT STEPS
  • Study the properties of linear operators in vector spaces
  • Learn about the implications of the Rank-Nullity Theorem
  • Explore examples of linear independence in finite-dimensional spaces
  • Investigate the application of the Cayley-Hamilton theorem in linear algebra
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, vector spaces, and linear transformations. This discussion is beneficial for anyone looking to deepen their understanding of linear independence and operator theory.

mivanova
Messages
7
Reaction score
0
Can you help me with this, or at least give me an idea how to proceed:
Let T:V->V be a linear operator on the vector space over the field F. Let v is in V and let m be a positive integer for which v is not equal to 0, T(v) is not equal to 0, ...,T^(m-1)(v) is not equal to 0, but T^m(v) is equal to 0. Show that {v, T(v), ... , T^(m-1)(v)} is linearly independent set.
Thank you!
 
Physics news on Phys.org
Given a_0 v + a_1 T(v) + \cdots + a_{m-1} T^{m-1}(v) = 0, apply T to both sides repeatedly and see what you get.
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
15
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
1
Views
2K
Replies
34
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K