Show that d^4k is Lorentz invariant

In summary, to show that ##d^4k## is Lorentz Invariant, we can use the transformation property of ##k^u## and the Minkowski metric ##\eta_{uv}##. By expressing ##d^4k## in terms of index notation and applying it to the moving frame, we can show that the effects of length contraction and time dilation cancel out, making the volume element invariant under a Lorentz transformation. This can also be seen in momentum space with the components ##k_1, k_2, k_3, k_4##.
  • #1
binbagsss
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Homework Statement


Show that ##d^4k## is Lorentz Invariant

Homework Equations


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Under a lorentz transformation the vector ##k^u## transforms as ##k'^u=\Lambda^u_v k^v##
where ##\Lambda^u_v## satisfies ##\eta_{uv}\Lambda^{u}_{p}\Lambda^v_{o}=\eta_{po}## , ##\eta_{uv}## (2) the Minkowski metric, invariant.

The Attempt at a Solution


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I think my main issue lies in what ##d^4k## is and writing this in terms of ##d^4k##
Once I am able to write ##d^4k## in index notation I might be ok.
For example to show ##ds^2=dx^udx_u## is invariant is pretty simple given the above identities and my initial step would be to write it as ##ds^2=\eta_{uv}dx^udx^v## in order to make use (2).
I believe ##d^4k=dk_1 dk_2 dk_3 dk_4##?
For example given a vector ##V^u = (V^0,V^1,V^2,V^3)## I don't know how I would express ##V^0V^1V^2V^3## as some sort of index expression of ##V^u## (and probably I'm guessing the Minkowski metric?). I would like to do this for ##d^4k##.
Is this the first step required and how do I go about it?

Many thanks in advance.
 
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  • #2
Length contraction and time dilation "cancel" in a volume element.

For simplicity, have the moving frame be moving along the x axis.
dx = gamma dx'
dt = dt' /gamma
dy = dy'
dz = dz'

dxdydzdt = dx'dy'dz'dt' gamma/gamma = dx'dy'dz'dt'

Same applies to momentum space with k1,k2,k3,k4
 
  • #3
DuckAmuck said:
Length contraction and time dilation "cancel" in a volume element.

For simplicity, have the moving frame be moving along the x axis.
dx = gamma dx'
dt = dt' /gamma
dy = dy'
dz = dz'

dxdydzdt = dx'dy'dz'dt' gamma/gamma = dx'dy'dz'dt'

Same applies to momentum space with k1,k2,k3,k4

huh? using the relevant equations please?
don't think i'd get the marks if I plucked something out of the air ...
 
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