Show that he object moves on an elliptical path

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SUMMARY

An object moves in the xy-plane following the position vector r = i a cos(ωt) + j b sin(ωt), where a, b, and ω are constants. This motion describes an elliptical path defined by the equation (x/a)² + (y/b)² = 1. By substituting x = a cos(ωt) and y = b sin(ωt) into the elliptical equation, it is confirmed that the relationship holds true for all values of t.

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Saladsamurai
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Okay then :smile:

Homework Statement



An object moves in the xy-plane such that its position vector is

\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) \qquad (1)

where a,b, and \omega are constants.

Show that the object moves on the elliptical path

(\frac{x}{a})^2+(\frac{y}{b})^2 =1 \qquad (2)


I have never studied ellipses, so I am 'googling' them now as we speak. I can see that (2) resembles the equation of a circle except that it includes a couple of scaling factors 'a' and 'b'.

I am just not sure how to relate (1) and (2) to each other.

Can I get a friendly 'nudge' here?

Thanks!

~Casey
 
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\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) = \bold{i}x +\bold{j}y

Right?

So x = a\cos(\omega t), y = b\sin(\omega t)

Just plug it into the equation (2) in order for it to hold it must hold for all t.
 
Feldoh said:
\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) = \bold{i}x +\bold{j}y

Right?

So x = a\cos(\omega t), y = b\sin(\omega t)

Just plug it into the equation (2) in order for it to hold it must hold for all t.

Right. I thought I was making it more difficult than it is. I don't know why I thought that there was something more to it. Thanks again! :smile:
 

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