Show that the given electric field is a plane wave

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Homework Help Overview

The discussion revolves around demonstrating that a given electric field represents a plane wave. Participants are analyzing the mathematical representation of wavefronts and their implications in the context of wave behavior.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the rearrangement of the wave equation and its interpretation as a plane equation. There is a focus on the relationship between the wavefronts and the conditions for a plane wave.

Discussion Status

Some participants have pointed out potential errors in the mathematical rearrangement and are exploring the implications of these corrections. There is an ongoing examination of whether the derived equation indeed signifies a plane wave, with some guidance suggesting that it may be simpler than initially thought.

Contextual Notes

Participants are considering the impact of time dependence in the equations and how it relates to the definition of a plane wave. There is an acknowledgment of the need for careful attention to signs and constants in the mathematical expressions.

Blanchdog
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Homework Statement
Show that each wavefront of the electric field forms a plane
Relevant Equations
## E(r, t) = E_0 \text{cos}(k(\hat{u} \cdot r - c t) + \phi)##
A wavefront is defined as a surface in space where the argument of the cosine has a constant value. So I set the argument of the cosine to an arbitrary constant s.

## k(\hat{u} \cdot r - c t) + \phi = s ##

The positional information is is in r, so I rearrange the equation to be

## \hat{u} \cdot r = \frac s k + ct + \phi = \text{const}##
## u_x x + u_y y + u_z z = \text{const} ##

And that's where I'm stuck.
 
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You made a small error in the rearrangement, but once corrected the last line is almost right; that's the general equation of a plane of normal ##\hat{n}##, but ##\hat{u} \cdot r## depends on ##t## so isn't constant in time (that's why the plane translates).
 
ergospherical said:
You made a small error in the rearrangement, but once corrected the last line is almost right; that's the general equation of a plane of normal ##\hat{n}##, but ##\hat{u} \cdot r## depends on ##t## so isn't constant in time (that's why the plane translates).
Whoops you're right, I wasn't very careful with my minus signs since I knew it was all going to be wrapped up into a constant anyway.

It looks like my equation is in the form of the scalar equation of a plane... is it really that simple? I have the equation of a plane so it is a plane wave?
 
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Blanchdog said:
It looks like my equation is in the form of the scalar equation of a plane... is it really that simple? I have the equation of a plane so it is a plane wave?
Yeah, pretty much 😄
 

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