Show that the given electric field is a plane wave

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SUMMARY

The discussion centers on demonstrating that a given electric field can be represented as a plane wave. The key equation derived is k(√{u} • r - ct) + φ = s, which describes a wavefront where the argument of the cosine remains constant. The participants clarify that while the equation resembles the scalar equation of a plane, it is essential to recognize that the term √{u} • r varies with time, indicating that the plane translates rather than remains static. This confirms that the derived equation indeed represents a plane wave.

PREREQUISITES
  • Understanding of wavefronts and plane waves in physics
  • Familiarity with vector notation and scalar equations
  • Knowledge of the relationship between wave propagation and time
  • Basic grasp of trigonometric functions, particularly cosine
NEXT STEPS
  • Study the properties of plane waves in electromagnetic theory
  • Explore the derivation of wave equations in different media
  • Learn about the implications of wavefront translation in physics
  • Investigate the role of phase constants in wave equations
USEFUL FOR

Students and professionals in physics, particularly those focusing on wave mechanics and electromagnetic theory, will benefit from this discussion.

Blanchdog
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Homework Statement
Show that each wavefront of the electric field forms a plane
Relevant Equations
## E(r, t) = E_0 \text{cos}(k(\hat{u} \cdot r - c t) + \phi)##
A wavefront is defined as a surface in space where the argument of the cosine has a constant value. So I set the argument of the cosine to an arbitrary constant s.

## k(\hat{u} \cdot r - c t) + \phi = s ##

The positional information is is in r, so I rearrange the equation to be

## \hat{u} \cdot r = \frac s k + ct + \phi = \text{const}##
## u_x x + u_y y + u_z z = \text{const} ##

And that's where I'm stuck.
 
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You made a small error in the rearrangement, but once corrected the last line is almost right; that's the general equation of a plane of normal ##\hat{n}##, but ##\hat{u} \cdot r## depends on ##t## so isn't constant in time (that's why the plane translates).
 
ergospherical said:
You made a small error in the rearrangement, but once corrected the last line is almost right; that's the general equation of a plane of normal ##\hat{n}##, but ##\hat{u} \cdot r## depends on ##t## so isn't constant in time (that's why the plane translates).
Whoops you're right, I wasn't very careful with my minus signs since I knew it was all going to be wrapped up into a constant anyway.

It looks like my equation is in the form of the scalar equation of a plane... is it really that simple? I have the equation of a plane so it is a plane wave?
 
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Blanchdog said:
It looks like my equation is in the form of the scalar equation of a plane... is it really that simple? I have the equation of a plane so it is a plane wave?
Yeah, pretty much 😄
 

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