Show this equality of limits - cross products

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SUMMARY

The limit of the cross product of vectors c and h, expressed as \(\lim_{\underline{h}\to 0} \frac{\underline{c} \times \underline{h}}{\|\underline{h}\|}\), does not equal zero in all cases. Specifically, when c is the unit vector \(\vec{i}\) and h approaches zero along the direction of \(\vec{j}\), the limit evaluates to 1, indicating that the limit is dependent on the path taken as h approaches zero. This demonstrates that the limit is not universally zero, contradicting the initial assertion.

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Homework Statement


Show that

[itex]\displaystyle\lim_{\underline{h}\to 0} \frac{\underline{c} \times \underline{h}}{\|\underline{h}\|} =0[/itex]

where c and h are vectors and x denotes cross product.

Homework Equations





The Attempt at a Solution



No idea how to do this?
 
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Ted123 said:

Homework Statement


Show that

[itex]\displaystyle\lim_{\underline{h}\to 0} \frac{\underline{c} \times \underline{h}}{\|\underline{h}\|} =0[/itex]

where c and h are vectors and x denotes cross product.

Homework Equations


The Attempt at a Solution



No idea how to do this?

I don't think it's true. Suppose the vectors are in R^3, with [itex]i,j,k[/itex] the usual coordinate vectors. Let [itex]c = i[/itex], [itex]h = tj[/itex]. (where [itex]t[/itex] is a scalar)

Then

[tex]\left|\frac{c \times h}{|h|}\right| = \left|\frac{tk}{|tj|}\right| = \frac{|tk|}{|tj|} = \frac{|t|}{|t|} = 1[/tex]

so the limit is certainly not zero as [itex]h[/itex] approaches zero along the [itex]i[/itex] coordinate axis. If the limit were zero, it would have to be zero no matter how [itex]h[/itex] approaches zero.
 


What happens if you let

[tex]\vec c = \vec i,\, \vec h = \lambda \vec j[/tex]

where [itex]\vec i,\vec j[/itex] are the standard unit vectors?
 

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