Show why an isolated electron cannot emit a photon

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Homework Help Overview

The discussion revolves around the problem of demonstrating why an isolated electron cannot emit a photon, using conservation laws of relativistic momentum and energy.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of assuming the electron emits a photon, leading to contradictions. They discuss the momentum and energy equations relevant to the scenario, questioning the relationship between initial and final energies of the electron.

Discussion Status

Participants are actively engaging with the problem, with some suggesting specific reference frames and equations. There is a recognition of the contradiction that arises when considering energy conservation, particularly regarding the energy of the photon. While some clarity is emerging, there is no explicit consensus on a final resolution.

Contextual Notes

Participants are working under the constraints of relativistic physics and are considering the implications of an isolated system, specifically the electron's state before and after the hypothetical emission of a photon.

asciola
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Homework Statement



"Use the laws of conservation of relativistic momentum and energy to show that an isolated electron cannot emit a photon."

Homework Equations


The Attempt at a Solution



So far I have tried to answer using the p = p' + q where q is the momentum of the photon, along with E^2 = p^2*c^2 + m^2*c^4, but am lost on how to prove that it is not possible to emit a photon.
 
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You can assume that it emits a photon and get a contradiction based on that.
As the choice of a reference frame is arbitrary, you can choose to have the electron at rest, initially, for example.
 
so if the electron is initially at rest that gives

p = 0 so 0 = p' + q

therefore

-p' = q and p'2 = q2

rewriting as

E2/c2 - m2*c2 = (h/λ)2

I feel like this isn't going in the right direction.
 
asciola said:
so if the electron is initially at rest that gives

p = 0 so 0 = p' + q

therefore

-p' = q and p'2 = q2

rewriting as

E2/c2 - m2*c2 = (h/λ)2

I feel like this isn't going in the right direction.

Ok, so the initial electron at rest has total energy mc^2. The final electron has some momentum p. What's the total energy of the final electron in terms of p?
 
Dick said:
Ok, so the initial electron at rest has total energy mc^2. The final electron has some momentum p. What's the total energy of the final electron in terms of p?

the only equation i can think of is E2 = p2c2 + m2c4
 
asciola said:
the only equation i can think of is E2 = p2c2 + m2c4

That's fine. So if you assume p is nonzero, which is larger, the initial energy of the electron or the final energy of the electron?
 
Dick said:
That's fine. So if you assume p is nonzero, which is larger, the initial energy of the electron or the final energy of the electron?

I think i know where this is going. So if the final energy is larger, then in order for energy to be conserved the energy of the photon would have to be negative, which is not possible.
 
asciola said:
I think i know where this is going. So if the final energy is larger, then in order for energy to be conserved the energy of the photon would have to be negative, which is not possible.

You've got it.
 
Dick said:
You've got it.

Thanks! I was thinking it would involve more equations to prove.
 
  • #10
asciola said:
Thanks! I was thinking it would involve more equations to prove.

Not this one. This one is easy. Taking the frame to be the rest frame of electron actually makes it pretty obvious.
 

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