Photon decay into Electron and Positron

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SUMMARY

The discussion centers on the impossibility of the reaction where a photon decays into an electron and a positron due to energy and momentum conservation laws. Specifically, the conservation of energy and momentum dictates that a massless and chargeless photon cannot produce two massive charged particles. The relevant equations include E(photon) = hf and p(photon) = hf/c, which illustrate the properties of photons and the constraints imposed by conservation laws.

PREREQUISITES
  • Understanding of photon properties, specifically masslessness and chargelessness.
  • Familiarity with the equations E(photon) = hf and p(photon) = hf/c.
  • Knowledge of conservation laws in physics, particularly conservation of energy and momentum.
  • Basic understanding of particle physics, including the characteristics of electrons and positrons.
NEXT STEPS
  • Study the principles of conservation of energy and momentum in particle interactions.
  • Explore the concept of 4-momentum in relativistic physics.
  • Investigate the conditions under which particle-antiparticle pairs can be created.
  • Learn about photon interactions in quantum electrodynamics (QED).
USEFUL FOR

Students of physics, particularly those studying particle physics and conservation laws, as well as educators seeking to explain the limitations of photon interactions in particle creation scenarios.

TheRedDragon
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Homework Statement



Show that the energy momentum conservation forbids the reaction (gamma)-> positron + electron,

Gamma is a photon, which is chargeless and massless

Homework Equations



E(photon)=hf
p(photon)=hf/c
Conservation of Energy
Conservation of Momentum
4-momentum

The Attempt at a Solution



My intuition is just to state that a massless and chargeless particle cannot create two particles with mass and charge. Is this correct?
 
Physics news on Phys.org
Nope.
 

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