Showing that x and 1+x² are solutions to this DE

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SUMMARY

The discussion focuses on demonstrating that the functions y = x and y = 1 + x² are solutions to the differential equation (1 - x²)(d²y/dx²) + 2x(dy/dx) - 2y = 0. Participants emphasize the importance of substituting these functions into the equation to verify that the left-hand side equals zero. This method confirms that both functions satisfy the differential equation, thereby establishing their validity as solutions.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear differential equations.
  • Familiarity with the process of differentiation, including first and second derivatives.
  • Knowledge of substitution methods in solving differential equations.
  • Basic algebraic manipulation skills to simplify expressions.
NEXT STEPS
  • Study the method of solving second-order linear differential equations with variable coefficients.
  • Learn about the Wronskian and its application in determining the linear independence of solutions.
  • Explore the concept of particular and homogeneous solutions in differential equations.
  • Investigate the role of initial conditions in solving differential equations.
USEFUL FOR

Students and professionals in mathematics, particularly those studying differential equations, as well as educators looking for examples of solution verification methods.

MuhTheKuh
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Hiya guys, I'm stuck on this new topic...
How do I show that x and 1+x² are both solutions to
(1-x²)*(d²y/dx²)+2x*(dy/dx)-2y=0
?

Thanks for your time
 
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A solution to a differential equation is one which, if you substitute it for y in your equation, you get zero on the left hand side like you're supposed to.

Can you substitute y=x and y=1+x2 into [tex](1-x^2)\frac{d^2 y}{dx^2} + 2x \frac{dy}{dx} - 2y[/tex] and see what you get?
 

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