Simple Capacitance Problem: Teflon-Filled Parallel-Plate Capacitor Calculation

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SUMMARY

The discussion focuses on calculating the capacitance and maximum voltage of a Teflon-filled parallel-plate capacitor with a plate area of 175 cm² and insulation thickness of 0.0500 mm. The relevant equations include C = Q/V and C = (constant)(A/d), where the dielectric constant for Teflon is crucial for determining capacitance. The insulation thickness is interpreted as the separation between the capacitor plates, which directly influences the capacitance value. The properties of Teflon, sourced from DuPont's data sheet, are essential for accurate calculations.

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  • Understanding of capacitance formulas, specifically C = (constant)(A/d)
  • Familiarity with dielectric materials and their properties
  • Basic knowledge of electrical concepts such as voltage and charge
  • Access to material property data sheets, particularly for Teflon
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  • Research the dielectric constant of Teflon and its impact on capacitance calculations
  • Learn about parallel-plate capacitor design and optimization techniques
  • Explore the relationship between insulation thickness and capacitance in capacitors
  • Study practical applications of Teflon in electrical components and devices
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Homework Statement



For a TeflonTM-filled parallel-plate capacitor having a plate area of 175 cm2 and insulation thickness of 0.0500 mm, determine the following:

a.)capacitance
b.)max volatge

Homework Equations



C = Q/V

C = (constant)(A/d)

The Attempt at a Solution



I understand the gist of this problem but I don't understand what the "insulation thickness" is supposed to do in this problem. Please help! thanks.
 
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I would read it as Teflon filled and the insulation thickness then would be the separation of the plates.

Not sure what resources you are supposed to employ to determine the properties of the Teflon in the problem, but here is a data sheet from DuPont for the electrical properties.
http://www2.dupont.com/Teflon_Industrial/en_US/tech_info/techinfo_compare.html
 
Yeah I see now. The Teflon acts as a dielectric and from there it isn't too hard to find the Voltage and Capacitance. Thanks a lot again!
 

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