Simple eigenvector question - please evaluate

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The discussion centers around verifying eigenvectors derived from the matrix A - I, specifically the matrix A - I = [[-0.5253, 0.8593, -0.1906], [-0.8612, -0.5018, 0.1010], [0.1817, 0.1161, -0.0236]]. The user proposes two eigenvector candidates: t = k(-0.0137, 0.225, 1) and t = k(-0.0088, 0.216, 1). A fellow forum member suggests calculating (A - I)x for both vectors to determine if either is an eigenvector, emphasizing that both vectors cannot be scalar multiples of each other due to their differing components.

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enc08
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Hi,

[tex]A - I =\begin{bmatrix} -0.5253 & 0.8593 & -0.1906 \\ -0.8612 & -0.5018 & 0.1010 \\ 0.1817 & 0.1161 & -0.0236\end{bmatrix}[/tex]

My eigenvector answer is

t= k(−0.0137,0.225,1)

My solution sheet's answer is

t = k(-0.0088, 0.216, 1)

Could I please ask that somebody checks this by hand? (not using an online solver as that's part of the problem).

A slightly awkward request but I appreciate anyone's answer.

I'm just seeking numerical confirmation. Thanks :)

(To save cluttering up this thread, I have already verified that I'm using the correct method here: https://www.physicsforums.com/showthread.php?t=668624)
 
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enc08 said:
Hi,

[tex]A - I =\begin{bmatrix} -0.5253 & 0.8593 & -0.1906 \\ -0.8612 & -0.5018 & 0.1010 \\ 0.1817 & 0.1161 & -0.0236\end{bmatrix}[/tex]

My eigenvector answer is

t= k(−0.0137,0.225,1)

My solution sheet's answer is

t = k(-0.0088, 0.216, 1)

Could I please ask that somebody checks this by hand? (not using an online solver as that's part of the problem).

A slightly awkward request but I appreciate anyone's answer.

I'm just seeking numerical confirmation. Thanks :)

(To save cluttering up this thread, I have already verified that I'm using the correct method here: https://www.physicsforums.com/showthread.php?t=668624)

I really don't want to go through all the arithmetic to hand-check your work, but you can check both purported vectors to see if either (or neither) works.

Let's call your vector xenc08 = <−0.0137, 0.225, 1>, and the one from the solution sheet xanswer = <-0.0088, 0.216, 1>

Calculate (A - I)x for both vectors. If one of the vectors is an eigenvector (or close to it), the result should be close to <0, 0, 0>.

Since both vectors have a component of 1, it can't be the case that your vector is a scalar multiple of the one shown in the answer sheet.
 
enc08 said:
Could I please ask that somebody checks this by hand?

Since it is your problem, wouldn't it make more sense that you check it by hand??
 

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