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Simple eigenvector question - please evaluate

  1. Mar 28, 2013 #1
    Hi,

    [tex]A - I =\begin{bmatrix} -0.5253 & 0.8593 & -0.1906 \\ -0.8612 & -0.5018 & 0.1010 \\ 0.1817 & 0.1161 & -0.0236\end{bmatrix}[/tex]

    My eigenvector answer is

    t= k(−0.0137,0.225,1)

    My solution sheet's answer is

    t = k(-0.0088, 0.216, 1)

    Could I please ask that somebody checks this by hand? (not using an online solver as that's part of the problem).

    A slightly awkward request but I appreciate anyone's answer.

    I'm just seeking numerical confirmation. Thanks :)

    (To save cluttering up this thread, I have already verified that I'm using the correct method here: https://www.physicsforums.com/showthread.php?t=668624)
     
  2. jcsd
  3. Mar 28, 2013 #2

    Mark44

    Staff: Mentor

    I really don't want to go through all the arithmetic to hand-check your work, but you can check both purported vectors to see if either (or neither) works.

    Let's call your vector xenc08 = <−0.0137, 0.225, 1>, and the one from the solution sheet xanswer = <-0.0088, 0.216, 1>

    Calculate (A - I)x for both vectors. If one of the vectors is an eigenvector (or close to it), the result should be close to <0, 0, 0>.

    Since both vectors have a component of 1, it can't be the case that your vector is a scalar multiple of the one shown in the answer sheet.
     
  4. Mar 28, 2013 #3

    micromass

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    Staff Emeritus
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    Since it is your problem, wouldn't it make more sense that you check it by hand??
     
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