Simple Harmonic Motion and pendulum clock

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SUMMARY

The discussion concludes that a spring clock is more suitable for use on the moon compared to a pendulum clock. The reasoning is based on the fact that the period of a pendulum clock is dependent on gravitational acceleration (g), which is significantly lower on the moon. In contrast, the spring clock operates independently of g, as its period is determined by the spring constant (k) and mass (m). Therefore, the spring clock will maintain a consistent rate on the moon, unlike the pendulum clock.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (SHM)
  • Familiarity with the equations of motion for springs and pendulums
  • Knowledge of gravitational acceleration and its effects on oscillatory motion
  • Basic physics concepts related to mass, force, and restoring forces
NEXT STEPS
  • Study the principles of Simple Harmonic Motion in detail
  • Learn about the effects of varying gravitational forces on pendulum clocks
  • Explore the mathematical derivation of the period for both spring and pendulum systems
  • Investigate practical applications of spring clocks in low-gravity environments
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in the practical applications of oscillatory motion in varying gravitational fields.

Ogir28
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Homework Statement



What will be better to take to the moon, a spring clock or a pendulum clock. Why?

Homework Equations



F= -k*(Delta)x

k = g m/Dx

T = 2*π*[square-root of:(m/k)]


The Attempt at a Solution



I know that there is less gravitational force while on the moon... Just don't see what the difference would be between block clocks. they both depend on gravity in the same manner...
 
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I'm not sure... but doesn't the equation read F=-kx, but k is NOT dependent on g? couldn't the spring be sideways?
 
well Usually we've been doing mass spring problems vertically, else, he would have told us... but what would be the factor that would affect a change in k while on the moon?
 
the only things that the equation involves are: mass, gravity, k constant
 
A pendulum would be better. For a pendulum, period is about 2pi*sqrt(l/g) This is dependent on g, which is different in the moon. It is dependent on g, because g is the restoring force which brings the mass at the end of the string back to equilibrium position. However, for a spring block oscillator, the mass of the object (ideally) doesn't contribute to the restoring force, which is just -k(Dx), and the period is independent of g.

Hope this helped.
 
The spring clock would be better because it will run at the same rate on the moon as it does on earth.
 
thank you guys very much.
 

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