An object of mass m is supended from a vertical spring of force constant 1269 N/m. When the object is pulled down 0.068 m from equilibrium and released from rest, the object oscillates at 10 Hz. The mass of the object is ____ kg. τ= 2∏*sqrt(M/K) M = mass K = spring constant 1/f = τ 3. The attempt at a solution 1/10 = .1 .1/2∏ = .15708 .157082 = M/K .024674*K = M .024674*1269 = 31.3113 and I keep getting told i have the wrong answer...help?