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An object of mass m is supended from a vertical spring of force constant 1269 N/m. When the object is pulled down 0.068 m from equilibrium and released from rest, the object oscillates at 10 Hz. The mass of the object is ____ kg.
τ= 2∏*sqrt(M/K)
M = mass
K = spring constant
1/f = τ
1/10 = .1
.1/2∏ = .15708
.15708^{2} = M/K
.024674*K = M
.024674*1269 = 31.3113
and I keep getting told i have the wrong answer...help?
τ= 2∏*sqrt(M/K)
M = mass
K = spring constant
1/f = τ
The Attempt at a Solution
1/10 = .1
.1/2∏ = .15708
.15708^{2} = M/K
.024674*K = M
.024674*1269 = 31.3113
and I keep getting told i have the wrong answer...help?