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Simple harmonic motion block and spring

  • Thread starter banfill_89
  • Start date
  • #1
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Homework Statement


A block, attached to a spring, is set into vertical oscillation with an amplitude of 25.0 cm and a frequency of 5.00 Hz. At t = 0.00 s, the block is 14.0 cm below the equilibrium position and is moving upwards. Assume that the displacement from equilibrium is given by
y = ym cos(ω t + φ ) , with y positive upwards.
Calculate the phase angle, φ.
(a) 5.31 rad
(b) 0.976 rad
(c) 4.12 rad
(d) 2.17 rad
(e) 1.87 rad

the answer is c....

Homework Equations



ive been using the equation that was given to me in the question, using 0.14m as my y, 0.25m as my ym, 0 as my t therefore w isnt needed? and i have a frequency??? im lost....please help lol

i am arriving at (b).....if this helps at all



The Attempt at a Solution

 

Answers and Replies

  • #2
turin
Homework Helper
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Did you use the fact that the block is moving upwards? Here's a hint: what is the numerical difference between b and c? Does it look familiar?
 
  • #3
47
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pi lol.....do i have to add pi? confusion
 
  • #4
turin
Homework Helper
2,323
3
do i have to add pi?
That was only a hint. Forget about [itex]\pi[/itex].

EDIT: Your y is wrong. Can you tell me why? (haha)

EDIT: EDIT: Wait a minute! THEIR y is wrong! Are you sure you copied every word of the problem correctly?
 
Last edited:

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