Simple Harmonic Motion of a body

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SUMMARY

The discussion focuses on calculating the speed of a body in simple harmonic motion (SHM) with an amplitude of 0.50 m and a period of 4π seconds. The correct formula for displacement is identified as x = A cos(2πft), where f is the frequency. By substituting the values of displacement (x = 0.30 m), amplitude (A = 0.50 m), and frequency (f = 1/(4π)), the calculated speed of the body is confirmed to be 0.20 m/s. The need to differentiate the displacement function to obtain the velocity function is also emphasized.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with trigonometric functions
  • Knowledge of differentiation in calculus
  • Ability to manipulate equations involving frequency and amplitude
NEXT STEPS
  • Study the derivation of velocity in simple harmonic motion
  • Learn about the relationship between amplitude, frequency, and period in SHM
  • Explore the concepts of energy conservation in simple harmonic motion
  • Investigate real-world applications of simple harmonic motion in physics
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Students studying physics, particularly those focusing on mechanics and wave motion, as well as educators teaching concepts related to simple harmonic motion.

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Homework Statement



A body is in simple harmonic motion of amplitude 0.50m and period 4pie seconds. What is the speed of the body when the displacement of the body is 0.30 m?



Homework Equations



Would it be x=Acos2(pie)ft ?

The Attempt at a Solution



I tried substituing in x= 0.30 and A=0.50 and f= (1/ 4pie)

The answer should be 0.20 ms^-1
 
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if the equation you gave was for displacement, then you will need to differentiate it to find the function of velocity.
 

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