Simple Harmonic Motion of a Pendulum

  • Thread starter bcjochim07
  • Start date
  • #1
bcjochim07
374
0

Homework Statement


What is the amplitude of a pendulum whose angle is given by (.10 rad)cos(5t + pi)
where t is in sec.



Homework Equations


s(t)=Acos(omega*t+phase constant)
Theta(t)=thetamax*cos(omega*t+phase constant)


The Attempt at a Solution


I'm not quite sure if I did this right:

I found the length of the string to be .392 m ( by using omega= sqrt(g/L)
So, using the small angle approximation s= .392 * sin theta where theta= the intial angle, which I found to be .1 rad by looking at the equation

s=(.392*sin(.1rad)) = .039 m

Then I used s(t) =Acos(omega*t + phase constant) with t=0
I also found omega= 5 and the phase constant is pi

.039 m = A cos(pi)
But my amplitude ends up negative. I've having a bit of trouble with positive and negative signs in SHM
 

Answers and Replies

  • #2
alphysicist
Homework Helper
2,238
2
Hi bcjochim07,

I think there are several things that are not quite right. The first and maybe the cause of the others is your identification of 0.1 radians as the initial angle. (The initial angle would be found by setting t=0 and solving for theta.)

So what would you say the angle 0.1 radians is? (It's actually mentioned in your formula for theta(t).)
 
Last edited:
  • #3
alphysicist
Homework Helper
2,238
2
Another issue that does not lead to a numerical error is that you used

s= r sin(theta) to find s=0.039 m

This gives the correct numerical value because theta is small (as it has to be for the pendulum to be in SHM), but s is actually the arc length along the pendulum's circular path so we would have

s = r theta

But the number you get looks right; now identify what that number represents (because of the particular angle that you used).
 
Last edited:
  • #4
SimonZ
25
0
Actually theta = (.10 rad)cos(5t + pi) is the expression for the pendulum with the variable the angle.
so 0.10 rad is the amplitude.
 
  • #5
alphysicist
Homework Helper
2,238
2
Hi bcjochim07,

In my two posts I asked you for the identification of two values that you found. The angle you found was the angular amplitude (as SimonZ stated) and the other (0.039 m) is the displacement amplitude (along the arc).
 
Last edited:

Suggested for: Simple Harmonic Motion of a Pendulum

Replies
6
Views
661
  • Last Post
Replies
8
Views
634
Replies
4
Views
329
  • Last Post
Replies
1
Views
567
  • Last Post
Replies
5
Views
427
  • Last Post
Replies
1
Views
467
  • Last Post
Replies
7
Views
650
  • Last Post
Replies
4
Views
530
Replies
6
Views
749
  • Last Post
Replies
5
Views
404
Top