Simple Harmonic Motion oscillations

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SUMMARY

The discussion focuses on calculating the periodic time of oscillations for a mass-spring system undergoing Simple Harmonic Motion (SHM). A mass of 0.49 kg is attached to a spring with a spring constant (k) of 19.8 N/m. The periodic time (T) is derived using the relationship T = 2π/ω, where ω is the angular frequency calculated from the equation k = mω². The calculated periodic time is T = 0.988 seconds.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (SHM)
  • Familiarity with spring constants and mass-spring systems
  • Knowledge of angular frequency (ω) and its relationship to periodic time (T)
  • Basic calculus, specifically second derivatives in motion equations
NEXT STEPS
  • Study the derivation of the SHM equations, focusing on T = 2π/ω
  • Explore the concept of angular frequency (ω) in more detail
  • Learn about the energy conservation in SHM systems
  • Investigate the effects of varying mass and spring constants on oscillation periods
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in the principles of oscillatory motion and spring dynamics.

kingyof2thejring
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A 0.49 kg mass attached to a spring (k = 19.8 N m-1) is performing SHM on a smooth horizontal surface. Calculate the periodic time of these oscillations, in s.

what equation links with T=2pi/w to give T or how do i use a=-ky/m.
thanks in advance
 
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if
F=ma= m*d^2y/dx^2 = -m*w^2*y = -ky
i get T=0.988
 
The linking equation you're looking for is:

[tex]k = m\omega^2[/tex]
 

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