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coffeem
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Homework Statement
A particle undergoes simple harmonic with amplitude of 10cm and frequency 5Hz. If it passes through the equilibrium position (x=0) at time t = 0, calculate the position, velocity and acceleration of the particle at t = 3.5m5 ms.
The Attempt at a Solution
Given that:
A = 0.1m
f = 5Hz
therefroe w = 2pif = 10pi
phase difference = 0.
So using the standard: x = Acos(wt+PD)
where PD = phase difference.
I get x = 0.1m.
differentiating this I get:
v = -0.34 m/s
and again differentiating I get:
a = -98.0 m/s^2.
However these answers appear to be wrong. Any advice on where I am messing up?