- #1

coffeem

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## Homework Statement

A particle undergoes simple harmonic with amplitude of 10cm and frequency 5Hz. If it passes through the equilibrium position (x=0) at time t = 0, calculate the position, velocity and acceleration of the particle at t = 3.5m5 ms.

## The Attempt at a Solution

Given that:

A = 0.1m

f = 5Hz

therefroe w = 2pif = 10pi

phase difference = 0.

So using the standard: x = Acos(wt+PD)

where PD = phase difference.

I get x = 0.1m.

differentiating this I get:

v = -0.34 m/s

and again differentiating I get:

a = -98.0 m/s^2.

However these answers appear to be wrong. Any advice on where I am messing up?