(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A particle undergoes simple harmonic with amplitude of 10cm and frequency 5Hz. If it passes through the equilibrium position (x=0) at time t = 0, calculate the position, velocity and acceleration of the particle at t = 3.5m5 ms.

3. The attempt at a solution

Given that:

A = 0.1m

f = 5Hz

therefroe w = 2pif = 10pi

phase difference = 0.

So using the standard: x = Acos(wt+PD)

where PD = phase difference.

I get x = 0.1m.

differentiating this I get:

v = -0.34 m/s

and again differentiating I get:

a = -98.0 m/s^2.

However these answers appear to be wrong. Any advice on where I am messing up?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Simple Harmonic Motion Question

**Physics Forums | Science Articles, Homework Help, Discussion**