Simple Harmonic Motion, spring periods

In summary, the conversation discusses investigating the mathematical relationship between the period of a spring and the mass attached to it. The equation T = 2pi SQRT(m/k) is used to find the spring constant (k). The conversation also mentions using Excel to plot T^2 vs. hanging mass and finding the best fit line, which can be used to determine the slope (4pi^2 /k). From the slope, the value of k can be calculated.
  • #1
Navras
4
0
Hi guys! I'd really like help with this as I'm stuck.

Homework Statement



Investigate the mathmatical relationship between period of a spring and mass.
Finding the spring constant (k) from measuring periods with a spring and different hanging masses.

Homework Equations



T = 2pi SQRT(m/k)

or rearranged

T^2 = ((4pi^2)/k) m

The Attempt at a Solution



Used Excel to plot T^2 vs. hanging mass. T^2 in seconds squared (y-axis) and hanging mass in kg (x-axis). Used Excel to find the best fit line.

Since I have plotted T^2 vs. m, does the slope equal (4pi^2)/k ?

I don't know where to go from here to get k though.



---

I've attached the graph I did also
 

Attachments

  • graph.jpg
    graph.jpg
    15.6 KB · Views: 8,448
Physics news on Phys.org
  • #2
Welcome to PF!

Navras said:
Since I have plotted T^2 vs. m, does the slope equal (4pi^2)/k ?

Yeah. The relationship is linear in m. All the stuff (the coefficient) that multiplies m is therefore the slope, just like in any other linear relationship.

Navras said:
I don't know where to go from here to get k though.

What do you mean? You have the slope, which is 4pi^2 /k, from the best fit line. Therefore, you have k.
 
  • #3
cepheid said:
What do you mean? You have the slope, which is 4pi^2 /k, from the best fit line. Therefore, you have k.

So, the slope is 1.5129, does that mean k is 1.5129 or

is it (4pi^2)/1.5129 = k?

thanks :)
 
  • #4
Navras said:
So, the slope is 1.5129, does that mean k is 1.5129 or

is it (4pi^2)/1.5129 = k?

thanks :)

I'm not telling you the answer to that, you should be able to arrive at it using the information you have (and it should be really clear) . Consider these two statements:

1. The slope is 4pi^2/k

2. The slope is 1.5129 (according to the Excel best fit curve).

What do you conclude?
 
  • #5


Hello,

It looks like you're on the right track in investigating the relationship between the period of a spring and mass. As you have correctly stated, the equation for the period of a spring is T = 2pi SQRT(m/k), where T is the period, m is the mass, and k is the spring constant.

By rearranging the equation, we can see that T^2 is directly proportional to m. This means that as the mass increases, the period of the spring will also increase. This is because a heavier mass requires more force to stretch the spring, resulting in a longer period.

In order to find the spring constant k, you can use your plotted data and the slope of the best fit line. The slope of the line should be equal to (4pi^2)/k. So, if you calculate the slope of your line, you can use it to solve for k.

I hope this helps. Keep up the good work in investigating the relationship between period and mass in simple harmonic motion!
 

1. What is Simple Harmonic Motion?

Simple Harmonic Motion is a type of periodic motion where a system oscillates back and forth around an equilibrium point, with a constant period and amplitude.

2. What is the period of a spring in Simple Harmonic Motion?

The period of a spring in Simple Harmonic Motion is the time it takes for one complete cycle of oscillation. It can be calculated using the equation T = 2π√(m/k), where T is the period, m is the mass of the object attached to the spring, and k is the spring constant.

3. How does the amplitude affect the period of a spring in Simple Harmonic Motion?

The period of a spring in Simple Harmonic Motion is not affected by the amplitude. This means that even if the amplitude of the oscillation changes, the period will remain constant as long as the other variables (mass and spring constant) stay the same.

4. What factors affect the period of a spring in Simple Harmonic Motion?

The period of a spring in Simple Harmonic Motion is affected by the mass of the object attached to the spring and the spring constant. A higher mass will result in a longer period, while a higher spring constant will result in a shorter period.

5. Can the period of a spring in Simple Harmonic Motion be changed?

Yes, the period of a spring in Simple Harmonic Motion can be changed by altering the mass or the spring constant. A higher mass or lower spring constant will result in a longer period, while a lower mass or higher spring constant will result in a shorter period.

Similar threads

  • Introductory Physics Homework Help
Replies
16
Views
395
  • Introductory Physics Homework Help
2
Replies
51
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
854
  • Introductory Physics Homework Help
Replies
20
Views
2K
Replies
13
Views
309
  • Introductory Physics Homework Help
Replies
6
Views
851
  • Introductory Physics Homework Help
Replies
24
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
4K
Back
Top