Simple Harmonic Motion, spring periods

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Homework Help Overview

The discussion revolves around the mathematical relationship between the period of a spring and the mass attached to it, specifically investigating how to determine the spring constant (k) from experimental data involving different hanging masses and their corresponding periods.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the linear relationship between T² and mass, questioning how to interpret the slope of the best fit line obtained from their data. There is uncertainty about whether the slope directly represents k or if it needs to be manipulated further to find k.

Discussion Status

Participants are actively engaging with the problem, exploring the implications of their findings and questioning their understanding of the relationship between the slope and the spring constant. Guidance has been offered regarding the interpretation of the slope, but no consensus has been reached on the final calculation of k.

Contextual Notes

There is an emphasis on using experimental data and the need for clarity in interpreting the mathematical relationships involved. Participants are encouraged to derive conclusions based on the information they have gathered from their experiments.

Navras
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Hi guys! I'd really like help with this as I'm stuck.

Homework Statement



Investigate the mathmatical relationship between period of a spring and mass.
Finding the spring constant (k) from measuring periods with a spring and different hanging masses.

Homework Equations



T = 2pi SQRT(m/k)

or rearranged

T^2 = ((4pi^2)/k) m

The Attempt at a Solution



Used Excel to plot T^2 vs. hanging mass. T^2 in seconds squared (y-axis) and hanging mass in kg (x-axis). Used Excel to find the best fit line.

Since I have plotted T^2 vs. m, does the slope equal (4pi^2)/k ?

I don't know where to go from here to get k though.



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I've attached the graph I did also
 

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Welcome to PF!

Navras said:
Since I have plotted T^2 vs. m, does the slope equal (4pi^2)/k ?

Yeah. The relationship is linear in m. All the stuff (the coefficient) that multiplies m is therefore the slope, just like in any other linear relationship.

Navras said:
I don't know where to go from here to get k though.

What do you mean? You have the slope, which is 4pi^2 /k, from the best fit line. Therefore, you have k.
 
cepheid said:
What do you mean? You have the slope, which is 4pi^2 /k, from the best fit line. Therefore, you have k.

So, the slope is 1.5129, does that mean k is 1.5129 or

is it (4pi^2)/1.5129 = k?

thanks :)
 
Navras said:
So, the slope is 1.5129, does that mean k is 1.5129 or

is it (4pi^2)/1.5129 = k?

thanks :)

I'm not telling you the answer to that, you should be able to arrive at it using the information you have (and it should be really clear) . Consider these two statements:

1. The slope is 4pi^2/k

2. The slope is 1.5129 (according to the Excel best fit curve).

What do you conclude?
 

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