Simple Harmonic Motion (tuning fork)

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To find the speed of the end of a tuning fork prong executing simple harmonic motion, both displacement and velocity equations are essential. The frequency is given as 1266 Hz, and the amplitude is 0.4944 mm, with a specific displacement of 0.2037 mm. The velocity can be calculated using the formula that incorporates these values, specifically the relationship between displacement, amplitude, and angular frequency. The discussion emphasizes the need to understand how displacement fits into the equations and the role of time in calculating speed. Proper application of these principles will yield the desired speed at the given displacement.
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Q. the end of on of the prongs on a tuning fork that executes simple harmonic motion of frequency 1266 hz has an amplitude of 0.4944mm. find the speed of the end of the prong when the end has a displacement of 0.2037mm.

okay i know that you use the v(t) equations and all but where does the displacent fit in and what about "t" in those equations i am lost please someone help
 
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