Simple harmonic oscillators-Quantum mechanics

[Jenkz]

Homework Statement

An ion in a harmonic ion trap sees a potential which is effectively that of a simple harmonic
oscillator. It has a natural oscillation frequency given by v = 1 MHz. Ignoring any internal
excitations, it is known to be in a superposition of the n = 0, 1 and 2 SHO energy states.
A measurement is then made and it is found to be in the n = 2 level.

a)What is the energy of the ion after the measurement has been made?

The Attempt at a Solution

Why is the answer E_n = (2n+1)/2 $$\hbar\omega$$

I do not understand the (2n+1) / 2

Thanks!

 

[Rajini]

Hi,
The average energy in the n^th state (or in the phonon picture: number of phonons in a mode associated with frequency $$\omega$$) for a single harmonic oscillator is given by:
$$E_n=\frac{2n+1}{2}\hbar\omega=(n+\frac{1}{2})\hbar\omega.$$
where
$$h\nu=\hbar\omega.$$