- #1
Peter G.
- 442
- 0
The question is the following:
y = (lower limit 0, upper limit e2x)∫ (1/T)
Find y'(2)
According to the markscheme, the answer is equal to 4e2. I got 2e2.
I did the following:
I integrated the expression, which yielded: 2√t. I then substituted the upper and lower limits in, which gave me:
2ex
I then differentiated that, which yields:
2ex
I proceeded to substitute 2 in, which gave me 2e2
Can anyone shed some light onto this for me please?
Thank you in advance!
y = (lower limit 0, upper limit e2x)∫ (1/T)
Find y'(2)
According to the markscheme, the answer is equal to 4e2. I got 2e2.
I did the following:
I integrated the expression, which yielded: 2√t. I then substituted the upper and lower limits in, which gave me:
2ex
I then differentiated that, which yields:
2ex
I proceeded to substitute 2 in, which gave me 2e2
Can anyone shed some light onto this for me please?
Thank you in advance!