The question is the following: y = (lower limit 0, upper limit e2x)∫ (1/T) Find y'(2) According to the markscheme, the answer is equal to 4e2. I got 2e2. I did the following: I integrated the expression, which yielded: 2√t. I then substituted the upper and lower limits in, which gave me: 2ex I then differentiated that, which yields: 2ex I proceeded to substitute 2 in, which gave me 2e2 Can anyone shed some light onto this for me please? Thank you in advance!