# Homework Help: Simple KVL, KCL and Ohm's Law problems

1. Aug 28, 2009

Given: In the circuit shown above, 192 V is dropped across the unknown resistor, Ro.

Required: Determine the value of Ro.

V = iR, KCL and KVL

I really don't know where to go on this one. I know that the right side's voltage will need to add up to zero, but that's about all I know.

Last edited: Aug 28, 2009
2. Aug 29, 2009

### djeitnstine

Call the current through the resistor $$R_o$$, $$I_o$$ and call the current through the sole $$20 \Omega$$ resistor $$I_1$$ then we know that:

$$I_o + I_1 = 16A$$ and starting from $$R_o$$ and going clockwise we have $$-192V - (20 \Omega) (I_o) + (20 \Omega)(I_1)=0$$

Subsequently, $$192 = I_o R_o$$.

3 equations and 3 unknowns.