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Simple KVL, KCL and Ohm's Law problems

  1. Aug 28, 2009 #1

    simple04_fg.png

    Given: In the circuit shown above, 192 V is dropped across the unknown resistor, Ro.

    Required: Determine the value of Ro.




    V = iR, KCL and KVL



    I really don't know where to go on this one. I know that the right side's voltage will need to add up to zero, but that's about all I know.
     
    Last edited: Aug 28, 2009
  2. jcsd
  3. Aug 29, 2009 #2

    djeitnstine

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    Gold Member

    Call the current through the resistor [tex]R_o[/tex], [tex]I_o[/tex] and call the current through the sole [tex]20 \Omega[/tex] resistor [tex]I_1[/tex] then we know that:

    [tex]I_o + I_1 = 16A[/tex] and starting from [tex]R_o[/tex] and going clockwise we have [tex]-192V - (20 \Omega) (I_o) + (20 \Omega)(I_1)=0[/tex]

    Subsequently, [tex]192 = I_o R_o[/tex].

    3 equations and 3 unknowns.
     
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