Simple KVL, KCL and Ohm's Law problems

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Given: In the circuit shown above, 192 V is dropped across the unknown resistor, Ro.

Required: Determine the value of Ro.

V = iR, KCL and KVL
I really don't know where to go on this one. I know that the right side's voltage will need to add up to zero, but that's about all I know.
 
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Call the current through the resistor [tex]R_o[/tex], [tex]I_o[/tex] and call the current through the sole [tex]20 \Omega[/tex] resistor [tex]I_1[/tex] then we know that:

[tex]I_o + I_1 = 16A[/tex] and starting from [tex]R_o[/tex] and going clockwise we have [tex]-192V - (20 \Omega) (I_o) + (20 \Omega)(I_1)=0[/tex]

Subsequently, [tex]192 = I_o R_o[/tex].

3 equations and 3 unknowns.