Simple pendulum problem - confirmation (1 Viewer)

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Hi, I got this question:
If a simple pendulum with length 1.50 m makes 72.0 oscillations in 180 s, what is the acceleration of gravity at its location?
Ok, for the period:

[tex]\frac{180\textit{s}}{72.0} = 2.50{\textit{s}}[/tex]

Then I found the pendulum equation that I don't understand well. I arraganged it to find the gravity:

[tex]g = \left( \frac{2\pi\sqrt{\ell}}{T} \right) ^2 [/tex]

Then I plugged in the numbers and got the answer. Did I do this correctly? :confused:
Last edited:


Homework Helper
Looks fine =)

But do feel free to clarify your doubts with the pendulum equation if you have any ^^

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving