Calculating Relative Velocities of Cars A and B | Simple Formula

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The relative velocity of Car A to Car B, both traveling east, is calculated by subtracting the velocity of Car B from Car A. With Car A at 30 mi/hr and Car B at 10 mi/hr, the correct calculation is 30 mi/hr - 10 mi/hr, resulting in a relative velocity of 20 mi/hr. The initial confusion stemmed from a miscalculation, but the concept of relative velocity was understood correctly. The discussion also included a light-hearted exchange about a weekend event. Overall, the focus remained on the correct application of the relative velocity formula.
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If Car A is going 30mi/hr east, and Car B is going 10mi/hr east. What is the relative velocity of Car A to Car B?

Wouldn't this just be Va - Vb = Vrelative? So.. 30mi/hr - 10mi/hr, the answer would be 20mi/hr?

Any help, thanks. :smile:
 
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Concept is right, but there is a mistake in your math.
 
Opps, lmao. huge mistake, I totally meant to write 20mi/hr. Anyway. Thanks!
 
thursday and taking abck sunday eh? good bands
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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