Simple Statics Question: Truss Structure

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SUMMARY

The discussion centers on analyzing a truss structure using the method of sections to determine equilibrium. Key equations of equilibrium, specifically ∑M = 0, ∑Fx = 0, and ∑Fy = 0, are employed to assess forces acting on the truss. The participant identifies the necessity of a support reaction in the X direction to maintain stability, particularly when considering member ED as a '2 force' member anchored at point E. This insight is crucial for ensuring the truss does not rotate and remains stable under load.

PREREQUISITES
  • Understanding of static equilibrium equations: ∑M = 0, ∑Fx = 0, ∑Fy = 0
  • Familiarity with truss analysis methods, particularly the method of sections
  • Knowledge of force members and their classifications, including '2 force' members
  • Basic principles of structural stability and support reactions
NEXT STEPS
  • Study the method of sections in truss analysis for detailed applications
  • Learn about the classification of force members in truss structures
  • Research the implications of support reactions in static equilibrium
  • Explore examples of truss stability and failure modes in engineering design
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Engineering students, structural analysts, and professionals involved in civil engineering or mechanical design who are focused on truss stability and analysis.

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Homework Statement


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Homework Equations


∑M = 0, ∑Fx = 0, ∑FY = 0

The Attempt at a Solution


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If so,

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If so, I will be using the method of sections to cut along the red line as indicated in the picture.

This gives me 3 equations of equilibrium as shown above. However, before solving these equations i first need to check whether my equations/diagrams are contain all the forces necessary.

I know that there is a support reaction in the Y direction of magnitude W at point A.
However, where do I put the support reaction in the x direction? From what I understand there needs to be a support reaction in the X direction as there is a moment generated from the W down and the W up.
 
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If you assume that ED is a zero force member, the truss will be unstable because it will only have one pinned support at A, and rotate clockwise toward the ground, taking the engine along with it. So this is an incorrect assumption. Instead, consider ED as a '2 force' member anchored at E.
 

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