Simple sum of forces parachute problem

kirby27
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a 64 kg parachutist falling vertically at a speed of 6.3 m/s impacts the ground, which brings him to a complete stop in a distance of .92 m. assuming constant acceleration after his feet first touch, what is the average force exerted on the parachutist by the ground?

i know:
Vf=0
Vi=6.3
delta Y = .92

i used (Vfy)^2=(Viy)^2+2a(deltaY)

and found a = -21.57

i then used F=ma: F= (65)(-21.57)

and got -1402 N

is this right?
 
on Phys.org
Correct method.

Is the force exerted by the ground upward, or is it downward?
 
i think the force exerted by the ground on the man is upward? should my answer be positive?
 
I would think so.
 

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