a 64 kg parachutist falling vertically at a speed of 6.3 m/s impacts the ground, which brings him to a complete stop in a distance of .92 m. assuming constant acceleration after his feet first touch, what is the average force exerted on the parachutist by the ground?(adsbygoogle = window.adsbygoogle || []).push({});

i know:

Vf=0

Vi=6.3

delta Y = .92

i used (Vfy)^2=(Viy)^2+2a(deltaY)

and found a = -21.57

i then used F=ma: F= (65)(-21.57)

and got -1402 N

is this right?

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# Simple sum of forces parachute problem

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