Simple Surface Integral of a Cylinder: Homework Statement and Solution Attempt

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SUMMARY

The discussion centers on calculating the surface integral of the vector field (x, -y, z) over the surface of a cylinder defined by x² + y² ≤ 4 and 0 ≤ z ≤ 1. The user successfully computes the integral using the divergence theorem, yielding a result of 4π. However, they struggle with the surface integral approach, mistakenly omitting contributions from the cylinder's flat ends, leading to an incorrect result of zero. The key takeaway is the importance of including all surface components in surface integrals.

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  • Understanding of vector calculus, specifically surface integrals
  • Familiarity with the divergence theorem
  • Knowledge of cylindrical coordinates
  • Ability to perform multivariable integration
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  • Study the application of the divergence theorem in vector calculus
  • Learn about surface integrals in cylindrical coordinates
  • Explore the contributions of boundary surfaces in integrals
  • Practice solving vector field integrals with various geometries
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Students and professionals in mathematics, physics, and engineering who are working with vector fields and surface integrals, particularly those dealing with cylindrical geometries.

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Homework Statement



This is annoying me because I am so clearly being a muppet somewhere. I need to integrate the vector field (x,-y,z).(vector)ds over the surface of a cyliner x^2 + y^2 < 4 (or equal to) and z is between 0 and 1.

The Attempt at a Solution



I have to do it both with and without divergence. With divergence, div(a) = 1, integral over a nice volume, gives me 4Pi, as O a, (integrating 2*r drd(theta)dz, with the specified limits.)

Trying to do it as a surface integral is driving me nuts. I end up integrating r^2(sin^2(x) - cos^(x) between the limits x = 0 and x = pi. as this integrates to sin(x)cos(x), this makes the entire integral zero.

So where am I going wrong?
 
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I don't think you included the contributions from the flat ends of the cylinder, did you?
 

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