Simplification of load on beam for Max M and D

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SUMMARY

The discussion focuses on simplifying the load analysis on a beam subjected to uniform distributed loads (UDL) without converting them to point loads. Participants explore methods to avoid complex calculations involving moments and double integrals for deflection formulas. A key insight is that it is possible to determine equivalent point loads that yield the same maximum moment and deflection, thereby streamlining the analysis process.

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  • Understanding of beam theory and load types
  • Familiarity with moment and deflection calculations
  • Knowledge of integration techniques in structural analysis
  • Experience with equivalent load transformations
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  • Research methods for calculating equivalent point loads from distributed loads
  • Study beam deflection formulas and their derivations
  • Learn about the application of the superposition principle in structural analysis
  • Explore software tools for beam analysis, such as SAP2000 or ANSYS
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Civil engineers, structural analysts, and students in engineering disciplines seeking efficient methods for load simplification and beam analysis.

Lisciu
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Guys I have tricky question :

I have beam loaded like that:
iG2eHoq.jpg


Is there any easy way to do simplification of this load ( I don't mean transfer the UDL to Point Load). Mentioned that I mean the way to not do the calculation of moment to find max in 4 section and the two almost 4 double integrals to get the deflection formula.

Is there a way to change all to point load sum up and place in some x position? Or there is no way to find this max moment and deflection formula easier way?
 
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Since deflection is the second integral of moment, you could conceivably find point loads that cause the same maximum moment in each section and it should provide identical maximum deflection.
 

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