Simplifying Complex Resistor Circuits

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The discussion focuses on simplifying complex resistor circuits for an upcoming E&M test. A method referred to as "pinching" wires is mentioned, raising questions about its reliability and effectiveness. One participant struggles with a specific homework problem, initially miscalculating the total resistance by incorrectly assuming a series configuration. The correct approach involves adding resistors in series and parallel as guided by the teacher, leading to a final answer of 7.5 Ω. Overall, the conversation emphasizes the importance of accurately identifying series and parallel configurations in circuit analysis.
jey1234
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Simplifying "Complex" Resistor Circuits

Homework Statement



Question 1:

I have an E&M test coming up and I'm having trouble simplifying complex circuits. Our teacher told us something about "pinching" the wires which I didn't really understand. I found the following link "http://www.allaboutcircuits.com/vol_1/chpt_7/3.html". I got the right solution for the homework problem using it but is this method reliable? Does it always work? Are there any other suggestions for tackling this type of problems?

Question 2

The attached problem is from homework. The question is what would an ohmmeter read between a and b. I don't understand these questions much. I simplified it to what is shown in the second attached image without much trouble. Now my intuition tells me that I should add these three remaining resistors (in series) and that's the answer (40.3 Ω) but that's apparently wrong. My teacher says that I should add the 7 Ω and 23.3 Ω together (in series). Then take the resulting 30.3 Ω resistor and add it with the 10 Ω (in parallel) and that gives 7.5 Ω, which is the correct answer. Can someone explain this to me please?

Please excuse the weird looking lines in the diagrams. I'm new to Visio. Thanks.

Homework Equations


The Attempt at a Solution



Attached.
 

Attachments

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  • Problem (Partially Solved).jpg
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Relative to points a and b, what is the parallel/series configuration? Don't get hung up on the particular way you have DRAWN them ... that is irrelevant. Follow the wires.
 


phinds said:
Relative to points a and b, what is the parallel/series configuration? Don't get hung up on the particular way you have DRAWN them ... that is irrelevant. Follow the wires.

Could you please elaborate? Thanks.
 


Not really. Redraw the circuit based on points a and b, not on some arbtrary configuration and maybe you'll see it.
 
jey1234 said:

Homework Statement



Question 1:

I have an E&M test coming up and I'm having trouble simplifying complex circuits. Our teacher told us something about "pinching" the wires which I didn't really understand. I found the following link "http://www.allaboutcircuits.com/vol_1/chpt_7/3.html". I got the right solution for the homework problem using it but is this method reliable? Does it always work? Are there any other suggestions for tackling this type of problems?

Question 2

The attached problem is from homework. The question is what would an ohmmeter read between a and b. I don't understand these questions much. I simplified it to what is shown in the second attached image without much trouble. Now my intuition tells me that I should add these three remaining resistors (in series) and that's the answer (40.3 Ω) but that's apparently wrong. My teacher says that I should add the 7 Ω and 23.3 Ω together (in series). Then take the resulting 30.3 Ω resistor and add it with the 10 Ω (in parallel) and that gives 7.5 Ω, which is the correct answer. Can someone explain this to me please?

Please excuse the weird looking lines in the diagrams. I'm new to Visio. Thanks.

Homework Equations


The Attempt at a Solution

attachment.php?attachmentid=52461&d=1351562575.jpg
attachment.php?attachmentid=52462&d=1351562575.jpg


Connect a battery across a & b. Now, what is the series/parallel combination for the resistors?
 


Thank you guys. I think I understand it better now after doing many similar problems. I just "followed the wires" :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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