Voltage and Current in a Combination Circuit

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scowl
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Homework Statement


All the batteries shown are 1 V.
Circuit schematic with a 20Ω resistor on the left and a 30Ω resistor on the right, each in a parallel branch between top and bottom wires; a 1V battery at top centre and two 1V batteries below it, all marked + and -.

What voltage is supplied by the batteries in this circuit?

What is the current through the branch of the circuit containing the 20 Ω resistor?

What is the current through the branch of the circuit containing the 30 Ω resistor?

What is the total current of the circuit?

What is the total resistance of the circuit?

Homework Equations


Voltage (V) = Current (I) / Resistance (R)

Ibranch = Vtotal / Rbranch

Itotal = Ibranch 1 + Ibranch 2 + ...

Rtotal = Vtotal / I total

The Attempt at a Solution


The problem is that I can't determine the effect of this arrangement of batteries. If the batteries were replaced with a single battery of, say, 3 V (or a series with this as the total), then the current through the 20 Ω resistor would be .15 A and the current through the 30 Ω resistor would be .1 A, the total current would be .25 A, resulting in the total resistance being 12 Ω.

However, with this battery arrangement, I can't determine if it would act as a series circuit with 3V or a parallel circuit with 2V. Additionally, I'm not sure what effect a parallel arrangement would have on the current of the entire circuit.
 
Series would be the batteries arranged end to end like this.
Two 1 V cells connected end to end in series, each with - and + terminals, the + of the first joined to the - of the second.

The result would be that the voltage would be cumulative of the batteries in the series.

Parallel would be the batteries arranged like this.
Two 1 V batteries drawn as rectangles stacked vertically, each with a minus terminal on the left and a plus terminal on the right, with both left terminals and both right terminals wired together in parallel.

The result would be that the voltage would be equal to that of a single battery (provided they all have the same voltage, which if they didn't would be another issue). However, the current would be cumulative.

So, given that the battery arrangement is two batteries in parallel acting as the first cell of a series, the voltage should be 2 V. However, all other examples I've seen of this arrangement had the second cell consisting of two batteries in parallel as well. Does this mean that the batteries in this problem will only have the current of a single battery?
 
scowl said:
Parallel would be the batteries arranged like this. Does this mean that the batteries in this problem will only have the current of a single battery?
current is not a matter of series or parallel, it is a matter of Ohm's Law.
 
scowl said:
Does this mean that the batteries in this problem will only have the current of a single battery?
You can imagine each of the two parallel cells contributing just half of the total current (this assumes they are perfectly identical in all respects). The single cell they connect to must carry the full current because it has no parallel twin to share with.