Voltage and Current in a Combination Circuit

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Homework Help Overview

The discussion revolves around a combination circuit involving batteries and resistors. Participants are exploring how the arrangement of batteries affects voltage and current in the circuit, particularly focusing on a scenario with 1 V batteries and resistors of 20 Ω and 30 Ω.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to analyze the circuit by comparing it to simpler arrangements of batteries and questioning whether the batteries act in series or parallel. Some participants discuss the implications of these arrangements on voltage and current, while others seek clarification on the application of Kirchhoff's laws and Ohm's Law in this context.

Discussion Status

Participants are actively engaging with the problem, questioning the assumptions about the battery arrangement and its impact on the circuit's behavior. There is an exploration of how current distribution works in series and parallel configurations, with some guidance offered regarding the contributions of batteries in parallel.

Contextual Notes

There is uncertainty regarding the specific arrangement of the batteries and how it influences the overall current and voltage in the circuit. Participants are also considering the implications of using identical batteries and the assumptions that come with that. The original poster expresses confusion about whether the circuit behaves like a series or parallel configuration.

scowl
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Homework Statement


All the batteries shown are 1 V.
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What voltage is supplied by the batteries in this circuit?

What is the current through the branch of the circuit containing the 20 Ω resistor?

What is the current through the branch of the circuit containing the 30 Ω resistor?

What is the total current of the circuit?

What is the total resistance of the circuit?

Homework Equations


Voltage (V) = Current (I) / Resistance (R)

Ibranch = Vtotal / Rbranch

Itotal = Ibranch 1 + Ibranch 2 + ...

Rtotal = Vtotal / I total

The Attempt at a Solution


The problem is that I can't determine the effect of this arrangement of batteries. If the batteries were replaced with a single battery of, say, 3 V (or a series with this as the total), then the current through the 20 Ω resistor would be .15 A and the current through the 30 Ω resistor would be .1 A, the total current would be .25 A, resulting in the total resistance being 12 Ω.

However, with this battery arrangement, I can't determine if it would act as a series circuit with 3V or a parallel circuit with 2V. Additionally, I'm not sure what effect a parallel arrangement would have on the current of the entire circuit.
 
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How do you determine series vs parallel and how does that apply to the battery arrangement?
 
Series would be the batteries arranged end to end like this.
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The result would be that the voltage would be cumulative of the batteries in the series.

Parallel would be the batteries arranged like this.
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The result would be that the voltage would be equal to that of a single battery (provided they all have the same voltage, which if they didn't would be another issue). However, the current would be cumulative.

So, given that the battery arrangement is two batteries in parallel acting as the first cell of a series, the voltage should be 2 V. However, all other examples I've seen of this arrangement had the second cell consisting of two batteries in parallel as well. Does this mean that the batteries in this problem will only have the current of a single battery?
 
Are you familiar with Kirchhoff's laws?
 
scowl said:
Parallel would be the batteries arranged like this. Does this mean that the batteries in this problem will only have the current of a single battery?
current is not a matter of series or parallel, it is a matter of Ohm's Law.
 
scowl said:
Does this mean that the batteries in this problem will only have the current of a single battery?
You can imagine each of the two parallel cells contributing just half of the total current (this assumes they are perfectly identical in all respects). The single cell they connect to must carry the full current because it has no parallel twin to share with.
 

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