Simplifying Expressions: 1/2 - 4/d

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Homework Help Overview

The problem involves simplifying the expression \( \frac{1}{2} - \frac{4}{d} \) divided by \( \frac{1}{d} + \frac{3}{2d} \). The subject area is algebra, specifically focusing on rational expressions and the use of least common denominators (LCD).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the least common denominator (LCD) and whether it should be applied to each term in the expression. There are questions about the correctness of multiplying the LCD across the entire expression and the resulting transformations of the terms.

Discussion Status

Participants have provided guidance on how to apply the LCD and have engaged in clarifying the steps involved in the simplification process. There is an ongoing exploration of interpretations regarding the final expression and its representation.

Contextual Notes

Some participants note the importance of proper bracket usage to avoid ambiguity in the final expression, highlighting potential misinterpretations of the simplified form.

priscilla98
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Homework Statement



Express in simplest form.
1/2 – 4/d divide by 1/d + 3/2d


Homework Equations



LCF

The Attempt at a Solution



I know the LCD is 2d. But would you multiply this to the equation
 
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You can multiply it as long as you do it to the numerator and the denominator. i.e.:

[tex] \frac{\frac{1}{2}-\frac{4}{d}}{\frac{1}{d}+\frac{3}{2d}} \times \frac{2d}{2d}[/tex]

Also, what you have there isn't really an equation. It is only an equation if there is an equals symbol somewhere.
 
Okay, but if you multiply the LCD which is 2d would you multiply 2d to 1/2, 4/d, 1/d and 3/2d

If so, i got 2d/4d - 8d/2d divided by 2d/2d^2 + 6d/2d^2, is this right?
 
priscilla98 said:
Okay, but if you multiply the LCD which is 2d would you multiply 2d to 1/2, 4/d, 1/d and 3/2d

If so, i got 2d/4d - 8d/2d divided by 2d/2d^2 + 6d/2d^2, is this right?

Yes you do multiply 2d by 1/2, 4/d, 1/d and 3/2d, but I am not quite sure what you have done there. [tex]\frac{1}{2}\times 2d = d[/tex]
[tex]\frac{4}{d}\times 2d = 8[/tex]
[tex]\frac{1}{d}\times 2d = 2[/tex]
[tex]\frac{3}{2d}\times 2d = 3[/tex]
 
Okay, i understand now. The final answer is d - 8/ 5, thanks a lot
 
priscilla98 said:
Okay, i understand now. The final answer is d - 8/ 5, thanks a lot

Yes, that is correct :smile:

As a side note, you should probably try to pay more attention to use of brackets. d-8/5 could be interpreted as d-(8/5) or as (d-8)/5, which are two completely different expressions.
 

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