Simplifying Fractions: Tips and Techniques for Combining Fractions

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To simplify the fractions (3x-6)/(x^2-3x+2) - (x^2-1)/(x^2-4x+4), first factor the denominators: x^2-3x+2 factors to (x-2)(x-1) and x^2-4x+4 factors to (x-2)^2. The least common denominator (LCD) is (x-2)^2(x-1). To combine the fractions, multiply the first fraction's numerator and denominator by (x-2) and the second fraction's numerator and denominator by (x-1). This allows for the fractions to be expressed with a common denominator, facilitating the subtraction process.
wocket92
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Hey, I need some help with simplifying these fractions.

(3x-6)/(x^2-3x+2) - (x^2-1)/(x^2-4x+4)

Im not quite sure what to do with the denominators. Am I supposed to change them to special forms? What is the process of making these a single fraction?
Thanks in advance.
 
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I would love to help you but It’s nearly impossible to tell what you mean!
3x-6/x^2-3x+2 - x^2-1/x^2-4x+4 could mean a ton of things, for example:

(3x-6/x^2)-3x+2 –( x^2-1)/(x^2-4x+4)
or
3x- (6/x^2) -3x+2 - x^2- (1/x^2) -4x+4

If I had to guess I would suspect you mean:
(3x-6)/(x^2-3x+2) – (x^2-1)/(x^2-4x+4)

If so factor the numerator and the denominator of each of these fractions.
 
wocket92 said:
Hey, I need some help with simplifying these fractions.

(3x-6)/(x^2-3x+2) - (x^2-1)/(x^2-4x+4)

Im not quite sure what to do with the denominators. Am I supposed to change them to special forms? What is the process of making these a single fraction?
Thanks in advance.
In order to add or subtract fractions, in algebra as in arithmetic, you must get "common denominators". And, again, as in arithmetic, you can get the least common denominator by factoring the denominators.

Here, x^2- 3x+ 2= (x- 2)(x- 1) and (x^2- 4x+ 4)= (x- 2)^2. The "least common denominator would be (x- 2)^2(x- 1). You can get that by multiplying both numerator and denominator of the first fraction by x- 2 and multiplying both numerator and denominator of the second fraction by x- 1.
 

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