Simplifying the Fourier Series Function: Tips & Tricks

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The discussion focuses on simplifying the Fourier series representation of a piecewise function defined as f(x) = 1 for 0 < t < 1 and f(x) = -1 for 1 < t < 2. The participants explore how to express this function in a different form, particularly through the use of sine series. It is established that for even n, the contribution to the series is zero, while for odd n, the series simplifies to a sum over odd integers. The transformation from n to 2n+1 is highlighted as a method to achieve this simplification. Understanding whether a function can be rewritten in another form involves analyzing its periodicity and symmetry properties.
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Homework Statement



f(x) = 1 0<t<1
= -1 1<t<2

How can I simplify this given that function(on the attachment).

What I mean is that how can I write the function in any other way?

In addition, How can I know if the function can be written in other form?
How can I write the function in other form?



Homework Equations





The Attempt at a Solution

 

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If n is even, 1- (-1)n= 1- 1= 0! If n is odd, 1- (-1)n= 1- (-1)= 2.

So
\frac{2}{\pi}\sum_{n=1}^\infty \frac{[1- (-1)^n] sin(n\pi t)}{n}
is just
\frac{2}{\pi}\sum \frac{2 sin(n\pi t)}{n}
where now the sum runs only over odd n. One way to show that is to use 2n+1 rather than n in the body of the sum. That way, as n goes over all non-negative integers, 2n+1 goes over all positive odd integers:
\frac{4}{\pi}\sum_{n=0}^\infty \frac{sin((2n+1)\pi t)}{2n+1}
 
Can 2n+1 be 2n-1 provided that n=1 to infinity?
How can I know if the function can be converted in some form?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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