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## Homework Statement

Find dy/dx.

[itex]y=sin^{2}(3x-2)[/itex]

## Homework Equations

## The Attempt at a Solution

Using the chain rule,

[itex]y=sin^{2}u[/itex]

[itex]y'=2sinucosu[/itex]

[itex]u=3x-2[/itex]

[itex]u'=3[/itex]

[itex]\frac{dy}{dx}=6sin(3x-2)cos(3x-2)[/itex]

Answer is:

[itex]3sin(6x-4)[/itex]

What am I missing here ?