No no no … you added, and then squared.Is this right?
(85.7cos(theta)+85.7sin(theta)=bcos30-85.7+bsin30)^2
7344.49cos^2(theta)+7344.49sin^2(theta)=b^2cos^2(90)-(85.7)^2+b^2sin90
1=(b^2cos^2(90)-(85.7)^2+b^2sin90)/7344.49x7344.49
No no no … you've put (bcos30 - 85.7)² = (bcos30)² - (85.7)².(85.7)²cos²θ=b²cos²90-(85.7)²
(85.7)²sin²θ=b²sin²90
(85.7)²cos²θ+(85.7)²sin²θ=b²cos²90-(85.7)²+b²sin²90
this is the same isnt it?
Hi Ry122!85.7²sin²(theta)+85.7²cos²(theta)=b²sin²30+b²cos²3 0-171.4bcos30+85.7²
sin²(theta)+cos²(theta)=(b²sin²30+b²cos²30-171.4bcos30+85.7²)/(85.7)^4
1=(b²sin²30+b²cos²30-171.4bcos30+85.7²)/(85.7)^4
Is this correct?
i had to get rid of the 2 85.7² on the left side so i moved them to the denominator on the right sideFirst, where did your "^4" come from??
Nooo … it should only be /(85.7)² at the end!85.7²sin²(theta)+85.7²cos²(theta)=b²sin²30+b²cos²3 0-171.4bcos30+85.7²
85.7² x 85.7² = 85.7^4
sin²(theta)+cos²(theta)=(b²sin²30+b²cos²30-171.4bcos30+85.7²)/(85.7)^4
Hi Ry122!so are you saying this is wrong?
5x²+10x²=15/1
5x²+10=15/1 x x²
5+10=15/1 x x² x x²