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Much like a pair of billiard balls, I would like to know if one can have two mobile objects collide with a still object at precisely the same time. Having all of the kinetic energy in both moving objects transfer into the one still object.

I can't really see why this isn't possible. However I imagine the scenarios where all the energy can be transferred and in the same direction would be few if any.

I was trying to figure out what the formula for this process would be. At first I thought it was simple adding of vectors. However I am concerned how exactly one would deal with 3 dimensional differences in direction.

For example if two billard balls strike another at precisely the same time. In a manner where the two moving balls followed a parallel path. Then the 3 ball would, I think still move straight forward ( as in along the same parallel) . Thou not at 2 times the speed of the original balls. That statement also implies the two moving balls have the same starting distance and equal speed at all times.

Now that example was only a 2 dimensional problem. If we have have a three dimensional collision for example:

For balls rolling down tubes at equal speeds and from equal distances, simultaniusly strike a ball in another tube. ( they would collide at the open ends of there respective tubes.) The four balls are arranged so there force is evenly distributed on a parallel path. ( think a square with an appropriately sized circle, being struck at the four corners if the square.) Once again I imagine the ball would move strait forward, but how much energy would it have? Also I guess a tube wouldn't work for the 5th ball as that would force the direction of the energy.

I'm not a student nor do I have much if any schooling in physics. So i aprecciate any time taken to consider my questions.