Sinc^2 as a delta function representation?

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Loro
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Hi, it's actually not homework but a part of my research.

I intuitively see that:

[itex]\lim_{t \rightarrow \infty} \frac{sin^2[(x-a)t]}{(x-a)^2} \propto \delta(x-a)[/itex]

I know it's certainly true of [itex]sinc[/itex], but I couldn't find any information about [itex]sinc^2[/itex]. Could someone give me a hint on how I could prove it, and find the proportionality coefficient?
 
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Loro said:
Hi, it's actually not homework but a part of my research.

I intuitively see that:

[itex]\lim_{t \rightarrow \infty} \frac{sin^2[(x-a)t]}{(x-a)^2} \propto \delta(x-a)[/itex]

I know it's certainly true of [itex]sinc[/itex], but I couldn't find any information about [itex]sinc^2[/itex]. Could someone give me a hint on how I could prove it, and find the proportionality coefficient?

A representation of the delta function should have integral 1. Put a=0 and integrate it. You'll find it needs more than just a constant normalization.
 
Thanks, so it seems:

[itex]\lim_{t \rightarrow \infty} \frac{1}{\pi t} \frac{sin^2[(x-a)t]}{(x-a)^2}[/itex]

does what I want.
 
Loro said:
Thanks, so it seems:

[itex]\lim_{t \rightarrow \infty} \frac{1}{\pi t} \frac{sin^2[(x-a)t]}{(x-a)^2}[/itex]

does what I want.

Sounds right.