1. The problem statement, all variables and given/known data A step down transformer, 2400/240 V, 50Hz has the following resistance and leakage parameters. Z1 = R1 + jX1 = 4 + j12 Ω Z2 = R2 + jX2 = 0.04 + j0.12 Ω The transformer is operating at 80% of its rated load. The power factor of the load is 0.866 leading. Determine the induced EMF in the primary side 2. Relevant equations E = 4.443 f N B A Ni = Hl = R phi phi = BA E = N d(phi)/dt 3. The attempt at a solution I don't know how to solve for N and phi. It's as if I'm leading nowhere. So far, I've got Attempt 1: a = V1/V2 = 2400/240 = 10 i1 = 2400/(4 + j12) = 60 - j180 = 189.7 cis (-71.57) but then if I try to use Ni=Hl I get stuck on finding H from B=uH Attempt 2: Try solving for N with L L = N^2/R N = sqrt(LR) R = 4 + j12 Substitute L = N^2/R into N = sqrt(LR) you just end up with N = N (nothing useful) Attempt 3: Transfer Z2 from the secondary side over to the primary side a= 2400/240 = 10 a^2 = 100 Z2' = 100 (0.04 + j0.12) = 4 + j12 Zeq = Z1 + Z2' = 2 (4 + j12) = 8 + j24 Then using Ni = R phi i = 2400/(8+j24) = 30 - j90 A R = 8 + j24 Then get stuck on finding phi... Attempt 4: using V1/V2 = N1/N2 2400/240 = N1/N2 Assume 100 turns in N1, then N2 = 10 turns. and let phi = i then E = 4.443 (50) (100) (60-j180) = some massive number in MegaVolts I've searched and searched in lecture notes for anything to do with the turns ratio, but can't find anything useful. Please help.