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TWest
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Singularity Spin Mechanics
Okay I within the last week too a look at a article about black hole spin and in this article it was said by a scientist that black hole's spin near the speed of light that are supermassive blazars I was thinking if a object is spinning wouldn't that make this massive object subject to angular momentum laws and found I think a equation that accurately explains this phenomena if this is the case. what happens is simple The black hole spins and opens a hole in event horizon allowing matter to escape where the spin counteracts the gravitational pull which I call a "Void zone or spot where the jet escapes" which makes a coordinate system. dx'∇ = dx(1-(∇Δv^2/C^2))^(1/2) which shows external spin pressure is making the singularity expand in a direction. Δv^2 = (Vg-Vs)^2 , Vg^2 = 2MbG / Rs, Vs^2 = Es/Mb
Final Equation
∇'(x',y',z') = ∇(1-(((2MbG / Rs) - (Es/Mb))^2/C^2))^(1/2)
Blazar means the number is Less than C at a point or more, and Supermassive black hole means all equal to C.
Does this seem possible to you guys?
Tory Cortland Weston 6/29/2013
Proof
Coords = http://www.wolframalpha.com/input/?i=dx'∇+=+dx(1-(∇Δv^2/C^2))^(1/2)+
Part I = http://www.wolframalpha.com/input/?i=2*M*G+/+R
part II = http://www.wolframalpha.com/input/?i=E/M
Article = http://www.gizmag.com/supermassive-black-hole-spin-nustar-Newton/26543/
Okay I within the last week too a look at a article about black hole spin and in this article it was said by a scientist that black hole's spin near the speed of light that are supermassive blazars I was thinking if a object is spinning wouldn't that make this massive object subject to angular momentum laws and found I think a equation that accurately explains this phenomena if this is the case. what happens is simple The black hole spins and opens a hole in event horizon allowing matter to escape where the spin counteracts the gravitational pull which I call a "Void zone or spot where the jet escapes" which makes a coordinate system. dx'∇ = dx(1-(∇Δv^2/C^2))^(1/2) which shows external spin pressure is making the singularity expand in a direction. Δv^2 = (Vg-Vs)^2 , Vg^2 = 2MbG / Rs, Vs^2 = Es/Mb
Final Equation
∇'(x',y',z') = ∇(1-(((2MbG / Rs) - (Es/Mb))^2/C^2))^(1/2)
Blazar means the number is Less than C at a point or more, and Supermassive black hole means all equal to C.
Does this seem possible to you guys?
Tory Cortland Weston 6/29/2013
Proof
Coords = http://www.wolframalpha.com/input/?i=dx'∇+=+dx(1-(∇Δv^2/C^2))^(1/2)+
Part I = http://www.wolframalpha.com/input/?i=2*M*G+/+R
part II = http://www.wolframalpha.com/input/?i=E/M
Article = http://www.gizmag.com/supermassive-black-hole-spin-nustar-Newton/26543/
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